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pishuonlain [190]
3 years ago
6

Which steps are needed to solve this equation? b+6= 21​

Mathematics
2 answers:
gregori [183]3 years ago
4 0
Subtract 6 from both sides then you get your answer; b=15
ratelena [41]3 years ago
3 0

Answer:

15

Step-by-step explanation:

Step 1:

b + 6 = 21        Equation

Step 2:

b = 21 - 6      Subtract 6 on both sides

Step 3:

b = 15    Subtract

Step 4:

15 + 6 = 21     Check Answer

Answer:

b = 15

Hope This Helps :)

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F(x)=20x when x is 0.25
7nadin3 [17]

Answer:

5

Step-by-step explanation:

just take the x away from the 20 and multiply 20(0.25)

Pretty easy when u know what you're doing

5 0
3 years ago
Find the midpoint of PQ¯¯¯¯¯¯¯¯ with endpoints P(−7, 0) and Q(1, 8). Then write an equation of the line that passes through the
Lilit [14]

Answer with Step-by-step explanation:

We are given that

P(-7,0) and Q(1,8)

We have to find the midpoint of PQ and write an equation of the line that passes through the midpoint.

Mid-point formula: x=\frac{x_1+x_2}{2}, y=\frac{y_1+y_2}{2}

By using this formula ,

The mid point of PQ

x=\frac{-7+1}{2}=-3, y=\frac{0+8}{2}=4

Hence, the midpoint of PQ is (-3,4).

Slope of PQ=m=\frac{y_2-y_1}{x_2-x_1}=\frac{8-0}{1+7}=1

Slope of perpendicular line=\frac{-1}{slope\;of PQ}=-1

The equation of line which is passing through the point (-3,4) with slope -1 is given by

y-y_1=m(x-x_1)

The equation of line which is passing through the point (-3,4) with slope -1 is given by

y-4=-1(x+3)

y-4=-x-3

y=-x-3+4

y=-x+1

6 0
4 years ago
JL has coordinates J(-6, 1) and L(-4,3).<br> Find the coordinates of the midpoint.
ikadub [295]

Answer:

The coordinates of the mid-point of JL are (-5 , 2)

Step-by-step explanation:

If point (x , y) is the mid-point of a segment whose end-points are (x_{1},y_{1}) and (x_{2},y_{2}), then x=\frac{x_{1}+x_{2}}{2} and  y=\frac{y_{1}+y_{2}}{2}

∵ JL is a segment

∵ The coordinates of J are (-6 , 1)

∴  x_{1} = -6 and  y_{1} = 1

∵ The coordinates of L are (-4 , 3)

∴  x_{2} = -4 and  y_{2} = 3

Lets use the rule above to find the mid-point of JL

∵ x=\frac{-6+-4}{2}=\frac{-10}{2}

∴ x = -5

∴ The x-coordinate of the mid-point is -5

∵ y=\frac{1+3}{2}=\frac{4}{2}

∴ y = 2

∴ The y-coordinate of the mid-point is 2

∴ The coordinates of the mid-point of JL are (-5 , 2)

5 0
4 years ago
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hoa [83]

Answer:

Step-by-step explanation:

[1,2]

local maxima means curve is curved downwards.

in [1,2] it is curved downward.

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