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miss Akunina [59]
3 years ago
9

A silo is a building shaped like a cylinder used to store grain. The diameter of a particular silo is 6.5 meters, and the height

of the silo is 12 meters.
Mathematics
1 answer:
hammer [34]3 years ago
6 0

Hey there! I'm happy to help!

To find the volume of a cylinder, you multiply the base by the height.

First, we find the base. The base is a circle. To find the area of a circle, you square the radius and multiply it by pi (we will use 3.14). The radius is half the diameter.

6.5/2=3.25

We square this.

3.25²=10.5625

And multiply by 3.14

10.5625(3.14)=33.16625

Now we multiply this by the height.

33.16625(12)=397.995

Therefore, the volume of this silo is 397.995 cubic meters.

Have a wonderful day! :D

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CD is a line parallel to AB and passes through the point (3, 5).
Mrac [35]

Answer:

y=5/3x+b

Step-by-step explanation:

Supposing CD uses the equation y=mb (meaning CD passes through the origin) and passes through (3,5), we then know the slope if 5/3 and the y intercept is 0. We can then write CD's equation as y=5/3x+0, or just y=5/3x.

So if AB is parallel to CB, then their equation is y=5/3x+b, as we don't the y-intercept yet.

Thank you!

4 0
2 years ago
A tree cast a shadow of 30m long and a 2m stick casts one that is 3m long. As show in the below diagram how tall is the tree?​
PSYCHO15rus [73]

Answer:

  • 20 m

Step-by-step explanation:

<u>We have similar triangles here.</u>

  • BC║DE, AB║AD and AC║AE ⇒ ΔADE ~ ΔABC

<u>The ratio of corresponding sides of similar triangles is same:</u>

  • BC/DE = AC/AE
  • BC / 2 = 30/3
  • BC / 2 = 10
  • BC = 2*10
  • BC = 20 m
6 0
3 years ago
Read 2 more answers
The polynomial 4x^3 - 6x^2 + 8x – 12 can be grouped in different ways to factor by
zubka84 [21]

Answer:

(4x3-6x) + (8x-12)= 2x

(4x3+8x) + (-6x2-12)= 2(2x-3) (x^2+2)

Step-by-step explanation:

All you have to do is simplify.

8 0
3 years ago
What type of proportion is shown in 12 : 4 = 24 : 8?​
Dmitry [639]

Answer:

3:1

Step-by-step explanation:

7 0
3 years ago
A bag contains two six-sided dice: one red, one green. The red die has faces numbered 1, 2, 3, 4, 5, and 6. The green die has fa
gayaneshka [121]

Answer:

the probability the die chosen was green is 0.9

Step-by-step explanation:

Given that:

A bag contains two six-sided dice: one red, one green.

The red die has faces numbered 1, 2, 3, 4, 5, and 6.

The green die has faces numbered 1, 2, 3, 4, 4, and 4.

From above, the probability of obtaining 4 in a single throw of a fair die is:

P (4  | red dice) = \dfrac{1}{6}

P (4 | green dice) = \dfrac{3}{6} =\dfrac{1}{2}

A die is selected at random and rolled four times.

As the die is selected randomly; the probability of the first die must be equal to the probability of the second die = \dfrac{1}{2}

The probability of two 1's and two 4's in the first dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^4

= \dfrac{4!}{2!(4-2)!} ( \dfrac{1}{6})^4

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^4

= 6 \times ( \dfrac{1}{6})^4

= (\dfrac{1}{6})^3

= \dfrac{1}{216}

The probability of two 1's and two 4's in the second  dice can be calculated as:

= \begin {pmatrix}  \left \begin{array}{c}4\\2\\ \end{array} \right  \end {pmatrix} \times  \begin {pmatrix} \dfrac{1}{6}  \end {pmatrix}  ^2  \times  \begin {pmatrix} \dfrac{3}{6}  \end {pmatrix}  ^2

= \dfrac{4!}{2!(2)!} \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= 6 \times ( \dfrac{1}{6})^2 \times  ( \dfrac{3}{6})^2

= ( \dfrac{1}{6}) \times  ( \dfrac{3}{6})^2

= \dfrac{9}{216}

∴

The probability of two 1's and two 4's in both dies = P( two 1s and two 4s | first dice ) P( first dice ) + P( two 1s and two 4s | second dice ) P( second dice )

The probability of two 1's and two 4's in both die = \dfrac{1}{216} \times \dfrac{1}{2} + \dfrac{9}{216} \times \dfrac{1}{2}

The probability of two 1's and two 4's in both die = \dfrac{1}{432}  + \dfrac{1}{48}

The probability of two 1's and two 4's in both die = \dfrac{5}{216}

By applying  Bayes Theorem; the probability that the die was green can be calculated as:

P(second die (green) | two 1's and two 4's )  = The probability of two 1's and two 4's | second dice)P (second die) ÷ P(two 1's and two 4's in both die)

P(second die (green) | two 1's and two 4's )  = \dfrac{\dfrac{1}{2} \times \dfrac{9}{216}}{\dfrac{5}{216}}

P(second die (green) | two 1's and two 4's )  = \dfrac{0.5 \times 0.04166666667}{0.02314814815}

P(second die (green) | two 1's and two 4's )  = 0.9

Thus; the probability the die chosen was green is 0.9

8 0
3 years ago
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