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Sauron [17]
4 years ago
12

What is 2 1\3 + 3 1\3

Mathematics
2 answers:
nlexa [21]4 years ago
6 0

Answer:

5\frac{2}{3}

Step-by-step explanation:

  1. 2 + 3 = 5
  2. 1/3 + 1/3 = 2/3
  3. Put them together: 5 2/3
saveliy_v [14]4 years ago
4 0

Answer:

The Fraction 21/3+31/3=17 1/3

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Which of the following describes the relationship between the area of a rectangle and its width, as width varies and length stay
sergejj [24]
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3 0
3 years ago
BRO I TRIED OVER AND OVER AGAIN AND I NEED HELP
torisob [31]

Answer:

Try 116?

Explanation:

First, let's us know the formula for finding area of a rectangle.

Formula - A = l * w

In the image, it shows the length (12) and width (10)

Length = L

Width = W

Now, what is 12 x 10? 120

Because we need the shaded region and the little box isn't apart of it, we need to find the area of that box to and subtract it from big box

The length is 2 and the width is 2, shown by the image.

2x2 = 4

120-4 = 116

4 0
1 year ago
If DE = 3x-5 and AC = 5x-3, find x.
deff fn [24]

Step-by-step explanation:

2(3x-5)=5x-3

6x -10 =5x -3

x=7

3 0
3 years ago
A rectangular tank, 25 cm long and 25 cm wide is filled with water to a depth of 10 cm. When a metal cube of edge 10 cm is place
Sophie [7]

The problem involves the volume of the water of the rectangular tank, so first we must find the volume of our water. For the volume we have;

\begin{gathered} \text{Volume = Lenght x Width x Height} \\ V_{water}_{}_{}\text{ = 25 x 25 x 10} \\ V_{water}=6250cm^3 \end{gathered}

Therefore our tank has an initial volume of 6250 cm³, but if you drop a cube with a side measuring 10 cm. the volume of the water in our tank increases. Giving us the expression;

\begin{gathered} \text{Volume Combined = Volume of Water + Volume of Cube} \\ V_{comb}=V_{water}+V_{cube} \end{gathered}

Since we already have the volume of the water (which is 6250), we just need to find the volume of the cube using the same formula (<em>Volume = Lenght x Width x Height</em>);

\begin{gathered} V_{comb}=V_{water}+V_{cube} \\ V_{comb}=V_{water}+(Lenght_{cube})(Width_{cube})(Height_{cube})_{}_{}_{} \\ V_{comb}=V_{water}+10(10)(10) \\ V_{comb}=6250+1000 \\ V_{comb}=7250cm^3 \end{gathered}

Therefore our new volume when they are combined or when the cube is droped in the tank is 7250 cm³.

But we must remember since our tank would remain it's shape no matter how much water it holds it would always retain it's dimension of it's lenght and width (25x25), therefore it is possible to find the height of the new water level using this logic;

\begin{gathered} V_{comb}=(Length_{\tan k})(Width_{\tan k})(Height_{water}\text{)} \\ V_{comb}=(25)(25)(Height_{water})\text{ , with our }V_{comb}=7250 \\ 7250=625(Height_{water}) \\ \text{Height}_{water}=\frac{7250}{625} \\ \text{Height}_{water}=11.6\text{ cm} \end{gathered}

Therefore the height of the new water level is 11.6 cm.

7 0
1 year ago
What is the range of the function graphed above? A. B. C. D.
Artist 52 [7]

Answer:

2 -3

Step-by-step explanation:

8 0
4 years ago
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