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3 years ago

What is the answer to this. 27-(7x3)

Mathematics

2 answers:

Soloha48 [4]3 years ago

7 0

6, because you do the parentheses first because of order of operations, and then you subtract that from 27

Hitman42 [59]3 years ago

4 0

So parentheses first then subtract that answer from the 27 7×3=21. 27-21=6

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Max measures the diagonal of a square room to be 32feet find the perimeter and area of the room round answers to the nearest ten

Rasek [7]

Hello!

To find the side length of a square with the diagonal you use the equation

$a = \sqrt{2} \frac{d}{2}$

a is side length
d is diagonal length

Put in the values you know

$a = \sqrt{2} * \frac{32}{2}$

Divide

$a = \sqrt{2} * 16$

Multiply

a = 22.6

All the sides are 22.6 feet

Add all the sides

22.6 + 22.6 + 22.6 + 22.6 = 90.4

The answer is 90.4

Hope this helps!

3 0

3 years ago

Find the area of this irregular figure. Please explain in steps how you did it so I know how to do it for the next question plea

Helen [10]

<h3>Answer: 426 square feet</h3>

Work Shown:

A = area of the rectangle

A = length*width

A = 26*15

A = 390 square feet

B = area of the triangle

B = base*height/2

B = 8*9/2

B = 72/2

B = 36 square feet

C = total area

C = A+B

C = 390+36

C = 426 square feet

7 0

1 year ago

What missing angle of the figure

aniked [119]

Answer:

138

Step-by-step explanation:

152+125=277

277-135=142

around 138

4 0

3 years ago

4x^2 y+8xy'+y=x, y(1)= 9, y'(1)=25

jarptica [38.1K]

Answer with explanation:

$\rightarrow 4x^2y+8x y'+y=x\\\\\rightarrow 8xy'+y(1+4x^2)=x\\\\\rightarrow y'+y\times\frac{1+4x^2}{8x}=\frac{1}{8}$

--------------------------------------------------------Dividing both sides by 8 x

This Integration is of the form ⇒y'+p y=q,which is Linear differential equation.

Integrating Factor

$=e^{\int \frac{1+4x^2}{8x} dx}\\\\e^{\log x^{\frac{1}{8}+\frac{x^2}{2}}\\\\=x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}$

Multiplying both sides by Integrating Factor

$x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\times [y'+y\times\frac{1+4x^2}{8x}]=\frac{1}{8}\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}\\\\ \text{Integrating both sides}\\\\y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\frac{1}{8}\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx \\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=\int {x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}} \, dx\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=-[x^{\frac{9}{8}}]\times\frac{ \Gamma(0.5625, -x^2)}{(-x^2)^{\frac{9}{16}}}\\\\8y\times x^{\frac{1}{8}}\times e^{\frac{x^2}{2}}=(-1)^{\frac{-1}{8}}[ \Gamma(0.5625, -x^2)]+C-----(1)$

When , x=1, gives , y=9.

Evaluate the value of C and substitute in the equation 1.

6 0

3 years ago

− 50 67 +1.5−100%

Alex73 [517]

Answer:

<em>Hello, I think the answer is -0.84 Hope That Helps!</em>

8 0

3 years ago

Read 2 more answers