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ad-work [718]
2 years ago
13

I NEED HELP AS SOON AS POSSIBLE Which of the following describes the location of the opposite of the number that R represents on

this line? vertical number line from negative 6 to positive 6 in increments of 2 is shown. Only the whole even numbers are labeled. A point labeled R is placed on the 2nd tick mark below the 0. At a distance of 4 tick marks above 0 At a distance of 4 tick marks below 0 At a distance of 2 tick marks below 0 At a distance of 2 tick marks above 0
Mathematics
1 answer:
Goryan [66]2 years ago
3 0

Answer:

At a distance of 4 tick marks above 0

Step-by-step explanation:

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In a class, every student knows French or German (or both). 15 students know French, and 17 students know German.
leva [86]
Answer:
32 students

Explanation:
We are given that:
Students in the class can either speak French, German or both
15 students know French
17 students know German

Now, the maximum number in the class can be calculated by assuming that no student can speak both languages.
This means that the number of students will be the summation of those who know French only (15) and those who know German only (17)

In this case:
the maximum number of students = 15 + 17 = 32 students 

Hope this helps :)
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2 years ago
Renting a movie from RedBox costs $1.29 each night, plus a one-time fee of $0.50. How much would it cost to rent a movie for 3 n
vitfil [10]
$4.37 for 3 $11.58 for 10
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3 years ago
A line passes through the points R(-1,-5) and S(-3,-1). Write the equation of the line through the point A(4,0) that is parallel
IRISSAK [1]
Sorry I was moving around taking the picture and my handwriting is sloppy. But I hope you understand how I got the answer

4 0
3 years ago
An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concen
devlian [24]

Answer:

(a) A 95% confidence interval for the population mean is [433.36 , 448.64].

(b) A 95% upper confidence bound for the population mean is 448.64.

Step-by-step explanation:

We are given that article contained the following observations on degrees of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:

420, 425, 427, 427, 432, 433, 434, 437, 439, 446, 447, 448, 453, 454, 465, 469.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

                              P.Q.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = \frac{\sum X}{n} = 441

            s = sample standard deviation = \sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }  = 14.34

            n = sample size = 16

            \mu = population mean

<em>Here for constructing a 95% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<em />

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.131 < t_1_5 < 2.131) = 0.95  {As the critical value of t at 15 degrees of

                                             freedom are -2.131 & 2.131 with P = 2.5%}  

P(-2.131 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.131) = 0.95

P( -2.131 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.131 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.131 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X -2.131 \times {\frac{s}{\sqrt{n} } } , \bar X +2.131 \times {\frac{s}{\sqrt{n} } } ]

                                      = [ 441-2.131 \times {\frac{14.34}{\sqrt{16} } } , 441+2.131 \times {\frac{14.34}{\sqrt{16} } } ]

                                      = [433.36 , 448.64]

(a) Therefore, a 95% confidence interval for the population mean is [433.36 , 448.64].

The interpretation of the above interval is that we are 95% confident that the population mean will lie between 433.36 and 448.64.

(b) A 95% upper confidence bound for the population mean is 448.64 which means that we are 95% confident that the population mean will not be more than 448.64.

6 0
3 years ago
Is 1/5 bigger or smaller than 1/6
MAXImum [283]
You can tell if you make the denominators the same easiest one is 30 for 6 and 5
1/5=6/30
1/6=5/30

now you can see which is bigger
4 0
3 years ago
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