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2 years ago

Help,??????????????????

Mathematics

1 answer:

abruzzese [7]2 years ago

8 0

So you would find out what number in the 9 times tables goes into 25 and there's your answer x

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Select all equations that could be used to find the measure of angle C, using the fact that the sum of all the angles in a trian

Semmy [17]

C = 180 - A - B

And

C = 180 - (A+B)

Hope I can help you :)
Brainliest answer :)) ?

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3 years ago

Please help!!!

Evgesh-ka [11]

D because you need to make the denominators have a common multiple.

5 0

2 years ago

Kelly runs a bakery that sells Chocolate Blizzards and Mint Breezes. The bakery must make at least 25 dozen and at most 45 dozen

drek231 [11]

Yeah Thanks I love to see that and the answer A

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2 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago

Skye needs 50 g of sugar to make 30 biscuits.

olga_2 [115]

Answer:600g

Step-by-step explanation: 50x3=150 150x4=600 since 30x4=120

5 0

2 years ago