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Neporo4naja [7]
3 years ago
12

Help,??????????????????

Mathematics
1 answer:
abruzzese [7]3 years ago
8 0
So you would find out what number in the 9 times tables goes into 25 and there's your answer x
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PLS HELP!!<br><br> KDJSKSKKSJDKS
Yuliya22 [10]
I think the answer is A.......
3 0
3 years ago
The price, e, of an entertainment system at extreme electronics is $220 less than twice the price, u, of the same system at ultr
MrMuchimi

Answer: The price of system at extreme electronics is $570 and the price of system at ultra electronics is $395.

Step-by-step explanation:

Let the price of the system at the ultra electronics be u

Let the price of the system at extreme electronics be e

According to question, we have

2u-e=220\\\\and\\\\e-u=175

Now, using the substitution method, we will solve the above system of equations.

e-u=175\\\\e=175+u

Now, put the value of u in the first equation :

2u-e=220\\\\2u-(175+u)=220\\\\2u-175-u=220\\\\u-175=220\\\\u=220+175\\\\u=\$395

Now, we put the value of u in the equation which is given by:

e=175+u\\\\e=175+395\\\\e=\$570

Hence, the price of system at extreme electronics is $570 and the price of system at ultra electronics is $395.

3 0
3 years ago
wrtie an equation in slope intercept form. A horizontal line that passes through a point 3 units below the origin
antoniya [11.8K]
In slope intercept form this would just be: y=-3
4 0
3 years ago
Find the following using number line.<br> 6 + 7 + 7
max2010maxim [7]
Wher is the number line duh
7 0
3 years ago
Which of the following is the complete list of roots for the polynomial function f (x) = (x squared 6 x 8) (x squared 6 x 13)? –
Sunny_sXe [5.5K]

The roots of the given polynomial function is {-4, -2, -3 + 2i, -3 - 2i}.

<h3>How to get the roots of the polynomial?</h3>

Here we have the polynomial function:

f(x) = (x^2 + 6x + 8)*(x^2 + 6x + 13)

So we just need to find the roots of the two quadratic functions, to do that, we use Bhaskara's formula.

For the first one, we have:

x = \frac{-6 \pm \sqrt{6^2 - 4*8} }{2} \\\\x = \frac{-6 \pm 2}{2}

So the two solutions are:

x = (-6 - 2)/2 = -4

x = (-6 + 2)/2 = -2

For the second quadratic we have:

x = \frac{-6 \pm \sqrt{6^2 - 4*13} }{2} \\\\x = \frac{-6 \pm 4i}{2}

So the two solutions are:

x = -3 + 2i

x = -3 - 2i

Finally, the list is:

{-4, -2, -3 + 2i, -3 - 2i}

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ4

8 0
2 years ago
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