The slope intercept form of the line whose points are (1,5) and (-2,-4) is y=3x+2.
Given two points of a line (1,5) and (-2,-4).
We have to form an equation in slop intercept form.
Equation is relationship between two or more variables which are expressed in equal to form.Equations of two variables looks like ax+by=c.
Point slope form of an equation is y=x+mc where m is slope of the line.
From two points the formula of equation is as under:
(y-
)=
*(x-
)
where
are the points.
Putting the values of
=1,
=-2,
=5 and
=-4.
y-5=(-4-5/-2-1)*(x-1)
y-5=-9/-3*(x-1)
y-5=3(x-1)
y-5=3x-3
y=3x-3+5
y=3x+2
Hence the slope intercept form of the line having points (1,5)(-2,-4) is y=3x+2.
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1) Find the derivative

and

.
2) The equation of the tangent line is

, so at point (2,6):

and


-the equation of the tangent line at point (2,6).
Answer:
1. work is the time it takes to move an object once acted upon by a force
Answer:
this is the correct answer look this img
Answer:
c
Step-by-step explanation:
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