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3 years ago

7

HELP ME PLZ (dont judge me im bad at math)

1 answer:

saveliy_v [14]3 years ago

3 0

7) 64%

8) 54%

9) 4/10, 40%

10) 17.5 miles

11) $10.50

12) $2.04

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Write an expression containing three terms that is in simplest form. One of the terms should be a constant.

sasho [114]

I believe that expression would be in the form
ax²+bx +c where, c is the constant term
For example; in the expression;
2x²+3x²+7 , 7 is the constant term.

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4 years ago

What is 2+2? <br><br> Wrong answers only

Fittoniya [83]

Answer:

3

Step-by-step explanation:

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3 years ago

Read 2 more answers

Simplify the expression<br> 70.7-5.76

Romashka-Z-Leto [24]

Answer:

64.94

Explanation

You arrange the numbers in such a way, to be in line with their decimal points like this:

70.7

-5.76

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3 years ago

We would like to create a confidence interval.

Vlada [557]

Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level $1-\alpha$ , we have the confidence interval with a margin of error of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

In this problem

The proportions are the same for all the options, so we are going to write our margins of error as functions of $\sqrt{\pi(1-\pi)}$

So

a.A 99% confidence level and a sample size of 50 subjects.

$n = 50$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}$

b.A 90% confidence level and a sample size of 50 subjects.

$n = 50$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}$

c.A 90% confidence level and a sample size of 300 subjects.

$n = 300$

90% confidence interval

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}$

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

$n = 300$

99% confidence interval

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The margin of error is

$M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}$

6 0

4 years ago

PLEASE HELP!!! PICKING BRAINLIEST ANSWER!<br>Equation: <img src="https://tex.z-dn.net/?f=2x%5E2%20-2x%20%3D%201" id="TexFormula1

zheka24 [161]

Answer:

I hope it will help you...

5 0

4 years ago