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2 years ago

9

Solve the quadratic equation: 2 + 4 = 0

1 answer:

dalvyx [7]2 years ago

8 0

Answers is 6=0 I think.

$2 + 4 = 0 \\ 6 = 0$

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Diameter of a sphere with the volume of 972πft^3

pogonyaev

$\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}~~
\begin{cases}
r=radius\\
-----\\
V=972\pi 
\end{cases}\implies 972\pi =\cfrac{4\pi r^3}{3}\implies \cfrac{3\cdot 972\pi }{4\pi }=r^3
\\\\\\
729=r^3\implies \sqrt[3]{729}=r\implies \boxed{9=r}$

now, recall that a diameter is twice as long as the radius, so the diameter is 2r.

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2 years ago

ANSWER !! <br> ILL GIVE 40 POINTS !!<br> DONT SKIP :(( <br> PLUS BRAINLIEST !

katen-ka-za [31]

Answer:

Step-by-step explanation:

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2 years ago

The ideal width of a safety belt strap for a certain automobile is 5 cm. An actual width can vary by at most 0.35 cm. Write and

notsponge [240]

Answer:

$4.65\leq x\leq 5.35$

Step-by-step explanation:

Let the actual width of belt be x

we are given that the ideal width of safety belt strap is 5 cm

So, Difference between actual and ideal = (x-5)cm

We are also given that An actual width can vary by at most 0.35 cm.

So, The difference between actual and ideal width should be less than or equal to 0.35 cm

So, $|x-5|\leq 0.35$

We know

$x-5\leq 0.35$ and $x-5\geq -0.35$

$x\leq 0.35+5$ and $x\geq -0.35+5$

$x\leq 5.35$ and $x\geq 4.65$

So, $4.65\leq x\leq 5.35$

Hence the range of acceptable widths is $4.65\leq x\leq 5.35$

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3 years ago

Answer the photo below thanks

Ad libitum [116K]

Answer:

6x60=360

Step-by-step explanation:

60

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2 years ago

Question 10, 4.A.27

anygoal [31]

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2 years ago