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bonufazy [111]
3 years ago
9

What is 24(a-41) +65 - 14

Mathematics
1 answer:
coldgirl [10]3 years ago
7 0
24a-984+65-14
24a-933 from there I don't know because they both don't have a variable
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SEE IMAGE! Two lines below intersect to form four angles, as shown. The measure of angle 2 is 114°. What is the sum of the measu
o-na [289]
ANSWER:


Angles 2 and 4 are vertical angles, which means they have the same angle measure because they are opposite of each other. So angles 2 and 4 are both 114 so that makes 228. All of the angles have to make 360, so 360 - 228 = 132. Then, 132/2 because there are two angles. That makes 66. And angles 1 and 3 are also vertical angles so they are also the same

The answer is 132
8 0
3 years ago
A-8<br> B-16<br> C-12<br> Please help guys.
Ksju [112]
Its c the answer is c because 8+4 is 12 and if you get rid of the angle and move the line so it’s straight it would be both 8 and 4
6 0
2 years ago
Find the area of the rhombus in m squared
Nataly [62]

Answer:

\boxed{\bold{100 \ m^2}}

Step By Step Explanation:

Area Of Rhombus: \bold{\frac{pq}{2} }

Identify 'p'

5 + 5 = 10

p = 10

Identify 'q'

10 + 10 = 20

q = 20

\bold{10 \ \cdot\ \ 20 \ = \ 200}

\bold{200 \ \div \ 2 \ = \ 100}

➤ \boxed{\bold{Mordancy}}

4 0
2 years ago
George and Paula are running around a circular track. George starts at the westernmost point of the track, and Paula starts at t
arsen [322]

Answer:

George is 43.20 ft East of his starting point.

Step-by-step explanation:

Let Paula's speed be x ft/s

George's speed = 9 ft/s

Note that speed = (distance)/(time)

Distance = (speed) × (time)

George takes 50 s to run a lap of the track at a speed of y ft/s

Meaning that the length of the circular track = y × 50 = 50y ft

George and Paula meet 14 seconds after the start of the run.

Distance covered by George in 14 seconds = 9 × 14 = 126 ft

Distance covered by Paula in 14 seconds = y × 14 = 14y ft

But the sum of the distance covered by both runners in the 14 s before they first meet each other is equal to the length of the circular track

That is,

126 + 14y = 50y

50y - 14y = 126

36y = 126

y = (126/36) = 3.5 ft/s.

Hence, Paula's speed = 3.5 ft/s

Length of the circular track = 50y = 50 × 3.5 = 175 ft

So, in 4 minutes (240 s), with George running at 9 ft/s, he would have ran a total distance of

9 × 240 = 2160 ft.

2160 ft around a circular track of length 175 ft, means that George would have ran a total number of laps (2160/175) = 12.343 laps.

Breaking this into 12 laps and 0.343 of a lap from the starting point. 0.343 of a lap = 0.343 × 175 = 60 ft

So, 60 ft along a circular track subtends an angle θ at the centre of the circle.

Length of an arc = (θ/360°) × 2πr

2πr = total length of the circular track = 175

r = (175/2π) = 27.85 ft

Length of an arc = (θ/360) × 2πr

60 = (θ/360°) × 175

(θ/360°) = (60/175) = 0.343

θ = 0.343 × 360° = 123.45°

The image of this incomplete lap is shown in the attached image,

The distance of George from his starting point along the centre of the circular track = (r + a)

But, a can be obtained using trigonometric relations.

Cos 56.55° = (a/r) = (a/27.85)

a = 27.85 cos 56.55° = 15.35 ft

r + a = 27.85 + 15.35 = 43.20 ft.

Hence, George is 43.20 ft East of his starting point.

Hope this Helps!!!

6 0
3 years ago
X/3 - ( -2) =16 and its 7 th grade algebra btw i need help
Novosadov [1.4K]

Answer x/3 -(-2)= 16

X/3+ 2=16

X/3=16-2

X/3=14

X= 14x3=42

Step-by-step explanation:

3 0
3 years ago
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