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Lesechka [4]
3 years ago
8

What is the recursive formula for this sequence10,14,18,22,26

Mathematics
1 answer:
ella [17]3 years ago
3 0

Answer:

your adding 4

Step-by-step explanation:

10

14

18

22

26

30

34

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We went over this like 3 times. It sounds and looks like pure gibberish
kipiarov [429]

Answer:

3 pencils

Step-by-step explanation:

eraser= 0.25

pencil= 0.75

2(0.25)= cost of erasers

0.5 + p=2.75 (p=pencils)

-0.5         -0,5

p=2.25

divide 2.25 by 0.75

=3

3 0
2 years ago
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
1 year ago
Pls help me find v,w,x,y, and z pls help me I will mark u brainlest
Eduardwww [97]

Answer:

v 39 degree

z 47 degree

x 94 degree

sry don't know about w and y....

4 0
3 years ago
What is the probability that a 44% free throw shooter will miss her next free throw?
stellarik [79]
The probability is 56/100 or 56%. Because they only got 44% of their previous throws, the probability that they'll miss the next one is 56%.
3 0
3 years ago
When a number is divided by 5 the answer is 3 remainder 4, what is that number?
skelet666 [1.2K]

We know that 5 fits entirely into our number three times, and then there's a remainder of 4.

If 5 fits three times exactly, it means that our number is at least 15 (5x3).

From here, we have a remainder of 4, which leads to 15+4=19

5 0
3 years ago
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