<u>Question 4</u>
1) bisects , , and (given)
2) (an angle bisector splits an angle into two congruent parts)
3) and are right angles (perpendicular lines form right angles)
4) and are right triangles (a triangle with a right angle is a right triangle)
5) (reflexive property)
6) (HA)
<u>Question 5</u>
1) and are right angles, , is the midpoint of (given)
2) and are right triangles (a triangle with a right angle is a right triangle)
3) (a midpoint splits a segment into two congruent parts)
4) (HA)
5) (CPCTC)
<u>Question 6</u>
1) and are right angles, bisects (given)
2) (reflexive property)
3) (an angle bisector splits an angle into two congruent parts)
5) (HA)
6) (CPCTC)
7) bisects (if a segment splits an angle into two congruent parts, it is an angle bisector)
<u>Question 7</u>
1) and are right angles, (given)
2) and are right triangles (definition of a right triangle)
3) (vertical angles are congruent)
4) (transitive property of congruence)
6) (HA theorem)
7) (CPCTC)
8) bisects (definition of bisector of an angle)
Answer:
C
Step-by-step explanation:
Its Mai
I promise I know why
You can try them out and see which one works.
a: f(2) = f(1) +6 = 5+6 = 11 . . . . . . not this one
b: f(1) = f(2) -6 = -1-6 = -7 . . . . . . not this one (5 ≠ -7)
c: f(2) = f(1) - 6 = 5 - 6 = -1 . . . . . this gives the right f(2)
d: f(2 = -6(f(1) = -6(5) = -30 . . . . not this one
_____
The appropriate choice is ...
... f(n +1) = f(n) - 6
— — — — —
You can also recognize that the next term is 6 less than the current one, so f(n+1) = f(n) - 6, which corresponds to the 3rd selection.
Do you have the a picture of the table
9514 1404 393
The first term is 2, so part of the recursive definition is ...
f(1) = 2
The common ratio is 6/2 = 3, so each term is 3 times the previous one. That part of the recursive definition is ...
f(n) = 3·f(n -1)
These two parts of the definition match choice C.