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schepotkina [342]
3 years ago
5

Radius of a circular ground is 21m. Find.

Mathematics
1 answer:
trapecia [35]3 years ago
6 0

The circumference of a circle of radius r is

C=2\pi r

So, in your case, the circumference is

C=2\cdot \pi \cdot 21 = 42\pi

The circumference is actually the length of the "perimeter", so the answer to questions 1 and 2 looks the same actually

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Can some one please help on number 8
Greeley [361]

X=13 1/3


So first  you have to add 16 +4 = 20. Then, simplify 3/2 to 1.5. Finally divide 20 by 1.5 = 13.333333333, or 13 1/3

6 0
3 years ago
Read 2 more answers
2. On December 31, Juan Carlos made a $ 7,000 deposit in an account that pays 2.975% interest compounded semi-annually. How much
inna [77]

Answer:$ 7425.89

Step-by-step explanation:

Formula to find the compound amount ( compounded semiannually) :-

A=P(1+\dfrac{r}{2})^{2n} , where P is the principal amount, r is rate of interest ( in decimal), and n is time in years.

Given : P= $7000

r=2.975%=0.02975

Time : n= 2

Then, The amount in account after 2 years:-

A=7000(1+\dfrac{0.02975}{2})^{2\times2}\\\\=7425.88565609\approx7425.89

Hence, Amount in account after 2 years = $ 7425.89

6 0
3 years ago
Find all complex solutions of X^2-5X -5= 0
denis-greek [22]

ANSWER

x  =  \frac{ 5  -  3\sqrt{ 5} }{2}  \: or \: x  =  \frac{ 5 +3 \sqrt{ 5} }{2}

EXPLANATION

The given equation is

{x}^{2}  - 5x - 5 = 0

The solution is given by the formula

x  =  \frac{ - b \pm \sqrt{ {b}^{2}  - 4ac} }{2a}

where a=1, b=-5, c=-5

We substitute into the formula to get;

x  =  \frac{ -  - 5 \pm \sqrt{ {( - 5)}^{2}  - 4(1)( - 5)} }{2(1)}

We simplify to get,

x  =  \frac{ 5 \pm \sqrt{ 45} }{2}

The solutions are:

x  =  \frac{ 5  -  3\sqrt{ 5} }{2}  \: or \: x  =  \frac{ 5 +3 \sqrt{ 5} }{2}

The equation has no complex roots.

4 0
3 years ago
Read 2 more answers
Simplify \sqrt{18x^7}
Slav-nsk [51]
\bf \sqrt{18x^7}\qquad 
\begin{cases}
18\\
\qquad 2\cdot 3\cdot 3\\
\qquad 2\cdot 3^2\\
x^7\\
\qquad  x^{2+2+2+1}\\
\qquad x^2\cdot x^2\cdot x^2\cdot x^1\\
\qquad (x^2)^3x^1\\
\qquad (x^3)^2x^1
\end{cases}\implies \sqrt{2\cdot 3^2\cdot (x^3)^2\cdot x}
\\\\\\
3\cdot x^3\sqrt{2\cdot x}\implies 3x^3\sqrt{2x}
5 0
3 years ago
Read 2 more answers
A new car dealer offered to sell her demonstrator model for 90% of the retail price.if the sale price was $9,750, what was the r
omeli [17]
The retail price would be $18,525
4 0
3 years ago
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