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2 years ago

Please help asap..................................

Mathematics

1 answer:

erik [133]2 years ago

6 0

Answer:

I think the answer is the point (-8,15) located in the sulatichon region

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If i roll 2 dice what is the probability that neither of them are prime nor even?

Eduardwww [97]

Answer:

There are 3 prime numbers shown on the die: 2, 3 and 5. The probability of showing a prime number on a single die is 1/2, hence the probability of not showing a prime number is also 1/2. Total possible outcomes when two dice are rolled = 6*6 = 36. Total possible outcomes when two dice are rolled = 6*6 = 36.

4 0

2 years ago

PLEASE HELP ASAP, WILL GIVE BRAINLIEST!

mojhsa [17]

Answer:6

Step-by-step explanation:

since it is A half circle it is the hhalf Value of the area of the full circle

3 0

2 years ago

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Mia discovered that if she takes half her age and adds 3, it produces the same results as taking one-fourth of her age and addin

Vikentia [17]

See https://web2.0calc.com/questions/help_29833.

5 0

2 years ago

The height h, in feet, of a ball that is released 4 feet above the ground with an initial velocity of 80 feet per second is a fu

gulaghasi [49]

Answer with Step-by-step explanation:

The height of the ball from the ground as a function of time is given by

$h(t)=-16t^2+80t+4$

The height of the ball at any instant of time can be found by putting the value of time 't' in the above relation as

Part a)

Height of ball after 2 seconds it is released is

$h(2)=-16\times 2^2+80\times 2+4=100feet$

Part b)

Height of ball after 4 seconds it is released is

$h(4)=-16\times 4^2+80\times 4+4=68feet$

4 0

3 years ago

Read 2 more answers

What are the solutions of the quadratic equation (x + 3)(x +3) = 49? Ax = -2 and x = -16 Bx = 2 and x = -10 Cx = 4 and x = -10 D

Ivahew [28]

Answer:

4 and -10

Step-by-step explanation:

$\displaystyle (x + 3)(x +3) = 49 \\ x^2+3x+3x+9=49 \\ x^2 +6x+9=49 \\ x^2 + 6x + 9 - 49 = 0 \\x^2+6x-40=0 \\\\ \Delta=b^2-4ac \\ \Delta=6^2-4 \cdot 1 \cdot (-40) \\ \Delta=36+160 \\ \Delta=196 \\ \\ X_{1,2}=\frac{-b \pm \sqrt{\Delta} }{2a} \\ \\ X_1=\frac{-b+\sqrt{\Delta} }{2a} = \frac{-6+14}{2} = \frac{8}{2}=4 \\ \\ X_2=\frac{-b-\sqrt{\Delta} }{2a} = \frac{-6-14}{2}=\frac{-20}{2} = -10$

4 0

3 years ago