Answer:
Step-by-step explanation:
∠ADC = 90°
∠ADB + ∠BDC = 90
20 + ∠BDC = 90
∠BDC = 90 - 20 = 70
∠BDC = 70°
16) ∠PSR = ∠PSQ +∠QSR
= 60 + 10
= 70
18) ∠PSR = 130
∠PSQ + ∠QSR = 130
90+ ∠QSR = 130
∠QSR = 130 - 90
∠QSR = 40
19)∠ADC = ∠ADB + ∠BDC
= 120 +20
= 140
20) ∠PSR = 125
Step-by-step explanation:
after x^2-4x-5 do sum and product
Given that the number of bridges has been modeled by the function:
<span>y=149(x+1.5)^2+489,505
To find the year in which, y=505000 we shall proceed as follows:
From:
</span>y=149(x+1.5)^2+489,505
substituting y=505000 we shall have:
505000=149(x+1.5)^2+489,505
simplifying the above we get:
0=149(x+1.5)^2-15495
expanding the above we get:
0=149x^2+447x+335.25-15495
simplifying
0=149x^2+447x-15159.8
solving the quadratic equation by quadratic formula we get:
x~8.69771 or x~-11.6977
hence we take positve number:
x~8.69771~8.7 years~9 years
thus the year in which the number will be 505000 will be:
2000+9=2009
Answer:
15504 different groups
Step-by-step explanation:
We have a total of 20 people, and we want to know how many groups of 5 people we can make, where the order of the people inside the group doesn't matter, so we can solve this question calculating the combination of 20 choose 5.
The formula for combination is:
C(n, p) = n! / (p! * (n-p)!)
In this case, we have n = 20 and p = 5, so:
C(20, 5) = 20! / (5! * 15!) = 20*19*18*17*16 / (5*4*3*2) = 15504
So we have 15504 different groups.
Answer:
the defence cards
Step-by-step explanation:
