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3 years ago

14

Kelly can type 120 words in 3 minutes. At that rate, how many words can she type in 5 minutes?

1 answer:

dem82 [27]3 years ago

4 0

I believe it is 200 words in 5 minutes.

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A group of three friends

Darina [25.2K]

Answer:

$4

Step-by-step explanation:

Each of the three friends orders a combo. If each drink is $2.50 and there are three drinks, that means the total cost of the pizza is $24. There are three combos, each with two slices of pizza, meaning there are six slices of pizza total. Then you divide 24 (the total cost of the pizza) by 6 (the total amount of slices), getting $4 per slice.

8 0

2 years ago

Tickets to a concert cost $70, or $20 with a student discount. Ticket sales must exceed $500,000 for the group to perform. If 20

Angelina_Jolie [31]

Solution:

Let x = the number of $70 seats sold

Let y = the number of $20 seats sold

x+y ≤ 20,000

70x+20y > 500,000

4 0

3 years ago

Read 2 more answers

If the sum of the measure of two angles in a triangle is 101, then the measure

LiRa [457]

Answer:

79 degrees.

Step-by-step explanation:

It is just a rule of trigonometry that all the angles inside ANY triangle will add up to 180 degrees.

There's only 3 possible angles in a triangle, so if you know what the sum of 2 are, its easy to find the last one.

All you have to do is 180 - 101, which equals 79 degrees.

Hope this helped : )

5 0

3 years ago

Read 2 more answers

Solve using long division <br> Please

madreJ [45]

1. $Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}$

$Steps:$

$\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}$

$\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}$

$\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}$

$\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}$

$\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}$

2. $Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}$

$Steps:$

$\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}$

$\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}$

$\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

4 0

3 years ago

PLEASE HELP ASAP PLEASE ANSWER CORRECTLY WILL GET BRAINLIEST

Xelga [282]

Answer:

True

Step-by-step explanation:

Each x input has 1 y output

5 0

3 years ago

Read 2 more answers