Using it's concept, it is found that a good estimate for the probability of drawing out a green block from the bag is of 0.67 = 67%.
<h3>What is a probability?</h3>
A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.
In this problem, to get a good estimate, we get the probability taking the outcomes from the sample, that is, 67 green blocks out of 100 blocks, hence:
p = 67/100 = 0.67.
A good estimate for the probability of drawing out a green block from the bag is of 0.67 = 67%.
More can be learned about probabilities at brainly.com/question/14398287
Answer:
5 9/14
7 1/2
Step-by-step explanation:
a) 4 1/7 + 1 1/2= 4+ 1/7 +1 +1/2 = 5 + 1/7 +1/2 = 5+ 2/14 + 7/14= 5 + 9/14= 5 9/14
b) 4 1/2 ÷ 3/5 = 9/2 ÷ 3/5 = 9/2 *5/3= 3/2*5= 15/2= 7 1/2
Answer:
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
The proportion of infants with birth weights between 125 oz and 140 oz is
This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So
X = 140
has a pvalue of 0.9772
X = 125
has a pvalue of 0.8413
0.9772 - 0.8413 = 0.1359
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.
Answer:
-2= 1/5x-2 +9
-2= -0.4 +9
Step-by-step explanation:
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