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Taya2010 [7]
3 years ago
15

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

t to x from the first equation is substituted into the second equation.
x + 4y = −9
2x + 5y = −6

A. 2x + 5(4y − 9) = −6
B. 2x + 5(−4y − 9) = −6
C. 2(4y − 9) + 5y = −6
D. 2(−4y − 9) + 5y = −6
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0
The answer would be D.
The only you thing you have to do is alter the first equation to isolate the x. You do that by moving the 4y to the other side, giving you:
x=(-4y-9)
Then you simply insert your new value for x into the second equation.
Hope this helps. :)
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Assume that a driver faces the following loss distribution:Outcome Probability12,000 0.15 0 0.851. What is the expected loss?2.
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Answer:

- 1800 ; 4284.8579 ;

Step-by-step explanation:

Given the table :

Outcome _____ probability

-12000 ________ 0.15

__ 0 __________ 0.85

Expected loss, m: Σx*p(x)

(-12000 * 0.15) + (0 * 0.85)

-1800 + 0 = - 1800

Standard deviation = sqrt(Var(x))

Var(x) = Σx²*p(x) - m²

(-12000^2 * 0.15) + (0^2 * 0.85)] - 1800^2

21,600,000 - 3240000

= 18360000

Standard deviation = sqrt(18360000)

Standard deviation = 4284.8579

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2 years ago
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Deffense [45]

Answer:

I think it is c correct me if I'm wrong

6 0
3 years ago
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The numbers of teams remaining in each round of a single-elimination tennis tournament represent a geometric sequence where an i
Anit [1.1K]

Answer:

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

Step-by-step explanation:

We are given the following in the question:

The numbers of teams remaining in each round follows a geometric sequence.

Let a be the first the of the geometric sequence and r be the common ration.

The n^{th} term of geometric sequence is given by:

a_n = ar^{n-1}

a_4 = 16 = ar^3\\a_6 = 4 = ar^5

Dividing the two equations, we get,

\dfrac{16}{4} = \dfrac{ar^3}{ar^5}\\\\4}=\dfrac{1}{r^2}\\\\\Rightarrow r^2 = \dfrac{1}{4}\\\Rightarrow r = \dfrac{1}{2}

the first term can be calculated as:

16=a(\dfrac{1}{2})^3\\\\a = 16\times 6\\a = 128

Thus, the required geometric sequence is

a_n = 128\bigg(\dfrac{1}{2}\bigg)^{n-1}

4 0
3 years ago
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Ghella [55]

Answer:

Yards: 83.58

Feet: 250.75

Inches: 3009

Step-by-step explanation:

Yards: 1 yard = 36 inches

3009/36= 83.58

So if each yard is 36 inches and there are 83.58 sets of 36 inches in 3009 then that's how many yards you have.

Feet: 1 foot = 12 inches

3009/12= 250.75

Again, if each foot is 12 inches and there are 250.75 sets of 12 inches in 3009 then that's how many feet you have.

Inches: It's already in inches :)

I hope this isn't confusing and I could help!

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first 1/8 then 4/8 and lastly 7/8
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