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4 years ago

Describe the transformation.

Mathematics

1 answer:

bogdanovich [222]4 years ago

4 0

The image in the link shows two similar figures with same y-coordinates, but different x-coordinates.

Further, the x-coordinates of the LHS figure is the product of -1 and the x-coordinates of the RHS figure, and vice-versa.

Hence, the two images are a reflection of each other.

Since, y - coordinates remain same, the figures show reflection across the y-axis

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If m<1 = 7x-19 and m<2 = x+5 find m<2

lbvjy [14]

Answer:55

Step-by-step explanation:

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3 years ago

Which of these are a litre unit:<br> Capacity, Mass, Density or Area?

Irina18 [472]

Answer:

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Step-by-step explanation:

I think mass is the litre unit

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3 years ago

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Which number is irrational, and integer, and a real number A) -4/2 B) there is no such number

Brut [27]

Answer:

Step-by-step explanation:

real number can be irrational or integer.

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4 years ago

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Work out the value of x in the following. (See photo)

AfilCa [17]

A) 2^(x+3)= 4^(2x)
make base number the same
2^(x+3)= 2^2 (2x)
set the exponents equal to eachother
x+3=2 (2x)
x+3=4x
-x both sides
3=3x
÷3 both sides
x=1

b) 16^(1/5)×2^(x)=8^(3/4)
make base same number
2^4 (1/5)×2^(x)=2^3 (3/4)
2^(4/5)×2^(x)=2^(9/4)
set exponents
4/5 +x=9/4
-4/5 both sides
x= 29/20

5 0

4 years ago

Chelsea took out three loans for a total of $ 78 comma 000 78,000 to start an organic orchard. Her business-equipment loan was

lianna [129]

Answer:

Business-equipment loan, A=$15000

Small-business loan, B=$24000

home-equity loan, C= $39000

Step-by-step explanation:

Let the Business-equipment loan at an interest rate of 11%=A

Let the small-business loan was at an interest rate of 5% =B

Let her home-equity loan was at an interest rate of 4.5%.=C

Since her total Loan=$78000

A+B+C=78000....(I)

Simple Interest = (P X R X T)/100

Since the Time, T=1 year

Interest on A = 0.11A

Interest on B = 0.05B

Interest on C = 0.045C

The total simple interest due on the loans in one year was $4605.

0.11A+0.05B+0.045C=4605....(II)

The annual simple interest on the home-equity loan was $105 more than the interest on the business-equipment loan.

0.045C = 0.11A +105...(III)

We proceed to solve the simultaneous equations.

A+B+C=78000....(I)

0.11A+0.05B+0.045C=4605....(II)

0.045C = 0.11A +105...(III)

From (III), 0.045C = 0.11A +105

Substitute 0.045C = 0.11A +105 into (II).

0.11A+0.05B+0.11A +105=4605

0.22A+0.05B=4500

From (III),

$C=\frac{22A}{9}+\frac{7000}{3}$

Substitute into (I)

$A+B+\frac{22A}{9}+\frac{7000}{3}=78000$

$\frac{31A}{9}+B=78000-\frac{7000}{3}$

$\frac{31A}{9}+B=\frac{227000}{3}$

$\frac{31A+9B}{9}=\frac{227000}{3}$

3(31A+9B)=9 X 227000

31A+9B=681000

0.22A+0.05B=4500 (Multiply by 9)

31A+9B=681000 (Multiply by 0.05)

1.98A+0.45B=40500

1.55A+0.45B=34050

Subtracting

0.43A=6450

A=$15000

From (III)

$C=\frac{22A}{9}+\frac{7000}{3}$

$C=\frac{22X15000}{9}+\frac{7000}{3} =39000$

C=$39000

from (I)

A+B+C=78000

15000+B+39000=78000

B=$24000

8 0

3 years ago