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Llana [10]
3 years ago
12

Describe the transformation.

Mathematics
1 answer:
bogdanovich [222]3 years ago
4 0

The image in the link shows two similar figures with same y-coordinates, but different x-coordinates.

Further, the x-coordinates of the LHS figure is the product of -1 and the x-coordinates of the RHS figure, and vice-versa.

Hence, the two images are a reflection of each other.

Since, y - coordinates remain same, the figures show reflection across the y-axis

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How do you do it????
m_a_m_a [10]

Answer:find the slope

Step-by-step explanation:

I don't know if you know how to find the slope if not reply back. But that's what the equation wants you to do.

6 0
3 years ago
Mike had $8.25 in his account. He deposited $2.25 on Tuesday. He then withdrew $5.75 for lunch on Wednesday. How much money does
Andre45 [30]

Answer:

<em>$4.75</em>

Step-by-step explanation:

(had) 8.25 + (deposited) 2.25 = (total) 10.50

10.50 - (withdrew) 5.75 = (total left) 4.75

6 0
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Cual es el valor de verdad de:<br><br> El rio magdalena es el rio más largo de colombia
allsm [11]
Yes, it is the longest river
5 0
2 years ago
Given the vertex of a quadratic function, find the axis of symmetry.
motikmotik

(i) The equation of the axis of symmetry is x = - 5.

(ii) The coordinates of the vertex of the parabola are (h, k) = (4, - 18). The x-value of the vertex is 4.

(iii) According to the <em>vertex</em> form of the <em>quadratic</em> equation, the parabola opens down due to <em>negative</em> lead coefficient and has a vertex at (2, 4), which is a <em>maximum</em>.  

<h3>How to analyze and interpret quadratic functions</h3>

In this question we must find and infer characteristics from three cases of <em>quadratic</em> equations. (i) In this case we must find a formula of a axis of symmetry based on information about the vertex of the parabola. Such axis passes through the vertex. Hence, the equation of the axis of symmetry is x = - 5.

(ii) We need to transform the <em>quadratic</em> equation into its <em>vertex</em> form to determine the coordinates of the vertex by algebraic handling:

y = x² - 8 · x - 2

y + 18 = x² - 8 · x + 16

y + 18 = (x - 4)²

In a nutshell, the coordinates of the vertex of the parabola are (h, k) = (4, - 18). The x-value of the vertex is 4.

(iii) Now here we must apply a procedure similar to what was in used in part (ii):

y = - 2 · (x² - 4 · x + 2)

y - 4 = - 2 · (x² - 4 · x + 2) - 4

y - 4 = - 2 · (x² - 4 · x + 4)

y - 4 = - 2 · (x - 2)²

According to the <em>vertex</em> form of the <em>quadratic</em> equation, the parabola opens down due to <em>negative</em> lead coefficient and has a vertex at (2, 4), which is a <em>maximum</em>.  

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

5 0
1 year ago
A parallelogram in a circumscribed circle must be a
Aleonysh [2.5K]
Hi!

//gm circumscribed by a circle must be a cyclic quadrilateral.
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