Which of the following are solutions to the quadratic equation? Check all that

Mathematics

2 answers:

lyudmila [28]3 years ago

8 0

Answer:

{-2, 1/3)

Step-by-step explanation:

Combine like terms in 2x2 + 7x - 2 =- x2 + 2x: We get:

3x^2 + 5x - 2 = 0

Use synthetic division from this point on. If the remainder in synthetic division is zero, the divisor is a root of the polynomial. Setting up this division for the possible root 3, we get:

3 / 3 5 -2

15 60

----------------------

3 20 58 The non-zero remainder tells us that 3 is NOT a

solution.

Try C: x = -2. Is this a solution?

-2 / 3 5 -2

-6 2

----------------------

3 -1 0 The zero remainder tells us that -2 is a solution (C)

The other factor is (3x - 1). If we set this equal to zero and solve for x, we get:

3x = 1, or x = 1/3. Thus B: 1/3 is the second solution.

Troyanec [42]3 years ago

3 0

Answer:

x = 1/3 or -2

Step-by-step explanation:

2x^2 + 7x - 2 = - x^2 + 2x

3x^2 + 5x - 2 = 0 (use factoring)

(3x − 1)(x + 2) = 0

3x - 1 = 0 OR x + 2 = 0

3x = 1 x = - 2

x = 1/3

Can you mark as brainliest? Hope it helps by the way!

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