Estimate. Divide using the standard algor ithm and check.

What is the domain of the graphed function?

frosja888 [35]

Yo sup??

Let the function be

y=f(x)

Domain refers to the permissible values of x

since its given that 1<x<5

therefore domain of the given function is x∈(1,5)

Hope this helps.

3 0

3 years ago

The longer base of a trapezoid is 8 ft. The longer base of a similar trapezoid is 13 ft. The area of the smaller trapezoid is 24

Licemer1 [7]

Answer:

390 ft²

Step-by-step explanation:

The longer base of a trapezoid is 8 ft. The longer base of a similar trapezoid is 13 ft. The area of the smaller trapezoid is 240 ft² What is the area of the larger trapezoid?

We solve the above question using proportion

(Longer base/Area of trapezoid) smaller trapezoid = (Longer base/Area of trapezoid) bigger trapezoid

Let the the Area of the bigger trapezoid = x

Hence,

= 8ft/240ft = 13ft/x ft

Cross Multiply

8ft × x = 240ft × 13ft

x = 240ft² × 12 ft/8 ft

x = 390 ft²

3 0

3 years ago

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

3 years ago

4x^5 in verbal algebraic expression

disa [49]

Answer:

The product of 4 times the quantity x to the fifth power

6 0

3 years ago

Given the set of integers one through 12 what is the probability choosing an odd number or a number greater than nine

snow_lady [41]

Answer:

1/4

Step-by-step explanation:

the numbers greater than nine are: 10,11,12

1,3,5,7,9

So that is nine numbers

9/12 can be simplified to 3/4 if you divide by 3

if you like my answer please give me the brainliest. I'm trying to boost my rank and I'm really close

7 0

3 years ago