Estimate. Divide using the standard algor ithm and check.

Toy shop orders 11 boxes of marbles each box contains six bags of marbles each bag contains 45 marbles how many marbles does the

WARRIOR [948]

Number of boxes = 11

1 box = 6 bags
11 boxes = 6 x 11
11 boxes = 66 bags

1 bag = 45 marbles
66 bags = 45 x 66
66 bags = 2970 marbles

Answer: The shop ordered 2970 marbles.

4 0

3 years ago

Y=x² + 16x + 64

motikmotik

I'll do the first one to get you started

The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64

Compare that to y = ax^2+bx+c and we see that

a = 1

b = 16

c = 64

Use the values of 'a' and b to get the value of h as shown below

h = -b/(2a)

h = -16/(2*1)

h = -8

This is the x coordinate of the vertex.

Plug this x value into the original equation to find the corresponding y value of the vertex.

y = x^2+16x+64

y = (-8)^2 + 16(-8) + 64

y = 0

Since the y coordinate of the vertex is 0, this means k = 0.

The vertex is (h,k) = (-8, 0)

---------------------

So we found that a = 1, h = -8 and k = 0

Therefore,

f(x) = a(x-h)^2 + k

f(x) = 1(x-(-8))^2 + 0

f(x) = (x+8)^2

is the vertex form

---------------------

<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>

8 0

4 years ago

What is 6.23 million written in scientific notation?

taurus [48]

Answer:

6.23*10^6

Step-by-step explanation:

We first write the answer in full notation 6,230,000.

Then we count how many decimal places it takes before we have one leading digit. Since it is six, we move the decimal place and write 6.23*10^6

7 0

2 years ago

CAN Someone help me out with Experimental probability.Ill give brainless

pentagon [3]

Answer:

1/4

Step-by-step explanation:

It is split into 8 equal parts, if you want to see how likely you're going to get red, look at how many red parts there are. 2. Now make it into a fraction! 2/8, but we need it to be simplified so it is 1/4.

Was that helpful?

4 0

4 years ago

Identify the sets that contain 2 as an element. (Check all that apply.)Check All That Apply{2, 3, 4, 5, ...}{2, 3, 4, 5, ...}{0,

Lady bird [3.3K]

Question:

Identify the sets that contain 2 as an element. (Check all that apply.)

$A.\ \{2, 3, 4, 5, ...\}$

$B.\ \{0, 1, 4, 9, ...\}$

$C.\ \{2, \{2\} \}$

$D.\ \{\{2\}, \{\{2\}\}\}$

$E.\ \{\{2\}, \{2, \{2\}\}\}$

$F.\ \{\{\{2\}\}\}$

Answer:

$A.\ \{2, 3, 4, 5, ...\}$

$C.\ \{2, \{2\} \}$

Step-by-step explanation:

Required

For which of the options is 2 an element

$A.\ \{2, 3, 4, 5, ...\}$

The elements of this set starts from 2, then 3 and continues as thus.

Hence: 2 is an element

$B.\ \{0, 1, 4, 9, ...\}$

From the given elements in the above set, 2 is not listed.

Hence: 2 is not an element of this set

$C.\ \{2, \{2\} \}$

Here, 2 is listed as an element, 2 is also listed as a subset.

Since 2 is listed as an element, then 2 is an element of the set.

$D.\ \{\{2\}, \{\{2\}\}\}$

Here, 2 is listed as a subset of {2} and also as a subset of subset of {{2}}.

Since 2 is not listed as an element itself, then 2 is not an element of the set.

$E.\ \{\{2\}, \{2, \{2\}\}\}$

Here, 2 is listed as a subset of {2} and also as a subset of subset of {2,{2}}. This set only contains subsets, i.e. 2 is not listed as a direct element of the set.

Hence: 2 is not an element of the set

$F.\ \{\{\{2\}\}\}$

Here, 2 is listed as a subset of subset of {{2}}. This set only contains subsets, i.e. 2 is not listed as a direct element of the set.

Hence: 2 is not an element of the set

5 0

3 years ago

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