If m angle 1 = 42 and m angle 2 = 27, then m angle APC =

Item 20 A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the sc

siniylev [52]

Answer:

The ratio of the area of the school banner to the area of the sign is <u>1944 cubic inches : 192.61 cubic inches.</u>

Step-by-step explanation:

Given:

A rectangular school banner has a length of 54 inches and a width of 36 inches. A sign is made that is similar to the school banner and has a length of 17 inches.

Now, to find the ratio of the area of the school banner to the area of the sign.

Dimensions of school banner :

Length = 54 inches.

Width = 36 inches.

Dimension of school sign:

Length = 17 inches.

So, to we find the width of sign by using cross multiplication method:

Let the width be $x.$

So, 54 is equivalent to 36.

Thus, 17 is equivalent to $x.$

$\frac{54}{36} =\frac{17}{x}$

By cross multiplying we get:

$54x=612$

Dividing both sides by 54 we get:

$x=11.33\ inches.$

Thus, the width of sign = 11.33 inches.

Now, to get the ratio of the area of the school banner to the area of the sign:

Area of the school banner : Area of the school sign.

= $54\times 36:17\times 11.33$

= $1944:192.61$

Therefore, the ratio of the area of the school banner to the area of the sign is 1944 cubic inches : 192.61 cubic inches.

6 0

3 years ago

Read 2 more answers

Enter the coefficients of the fifth Taylor polynomial T5(x) for the function f(x) = x5−3x4+2x2+5x−2 based at b=1. T5(x)= + (x−1)

DENIUS [597]

Compute the necessary values/derivatives of $f(x)$ at $x=1$ :

$f(1)=3$

$f'(1)=2$

$f''(1)=-12$

$f'''(1)=-12$

$f^{(4)}(1)=48$

$f^{(5)}(1)=120$

Taylor's theorem then says we can "approximate" (in quotes because the Taylor polynomial for a polynomial is another, exact polynomial) $f(x)$ at $x=1$ by

$T_5(x)=\dfrac3{0!}+\dfrac2{1!}(x-1)-\dfrac{12}{2!}(x-1)^2-\dfrac{12}{3!}(x-1)^3+\dfrac{48}{4!}(x-1)^4+\dfrac{120}{5!}(x-1)^5$

$T_5(x)=3+2(x-1)-6(x-1)^2-2(x-1)^3+2(x-1)^4+(x-1)^5$

###

Another way of doing this would be to solve for the coefficients $a,b,c,d,e,g$ in

$f(x)=a+b(x-1)+c(x-1)^2+d(x-1)^3+e(x-1)^4+g(x-1)^5$

by expanding the right hand side and matching up terms with the same power of $x$ .

5 0

2 years ago

3(2x+5)=36<br>what is the value of x

Bond [772]

$3(2x+5)=36\\
6x+15=36\\
6x=21\\
x=\frac{21}{6}$

6 0

3 years ago

Sarah went to an electronics store, purchased 3 CDs and 5 DVDs, and spent $137. Michelle went to the same store, bought 2 CDs an

vesna_86 [32]

C. thats the only one that will give you the same price for the DVDS as well. they charge $14 for CDS and $19 for DVDS

5 0

3 years ago

Read 2 more answers

Heather drove 265 miles using 10 gallons of gas. At this rate, how many gallons of gas would she need to drive 424 miles?

slava [35]

Answer:

Step-by-step explanation:

Next bit of info that we have is 424 miles. Miles go on the numerator, and gallons, which we will call "x" will go on the denominator. It should be set up like this: 265/10 = 424/x Once you cross multiply you should get 265x=4240. Divide 265 by both sides and the answer is 16 gallons. Sorry if its wrong

6 0

2 years ago