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Ad libitum [116K]
3 years ago
7

How to find the new interquartile range of the numbers 9,10,11,12,16,20,20

Mathematics
2 answers:
UNO [17]3 years ago
6 0

10 is ur range

hope this helps

muminat3 years ago
6 0

Answer:

The interquartile range would be 10.

Step-by-step explanation:

9, 10, 11, 12, 16, 20, 20

Median: 12

Lower quartile (Q1): 10

Upper quartie (Q2): 20

(IQR) Interquartile range: 20 - 10 = 10

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Elenna [48]

Answer:

the cube root of 262144 is 512

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If each of the following represents the slope of a line (or line segment), give the slope a line that is perpendicular to it. (a
Crank

Answer:

m_2 = -\frac{3}{4} -- (a)

m_2 = -\frac{7}{3} -- (b)

m_2 = -\frac{1}{4} --- (c)

m_2 = -3 -- (d)

Step-by-step explanation:

Given

a.\ m = \frac{4}{3}

b.\ m = \frac{3}{7}

c.\ m = 4

d.\ m = \frac{1}{3}

Required

Determine the slope of a perpendicular line

In geometry, the condition for perpendicularity is:

m_2 = -\frac{1}{m}

This formula will be applied in solving these questions.

a.\ m = \frac{4}{3}

m_2 = -\frac{1}{m}

Substitute 4/3 for m

m_2 = -\frac{1}{4/3}

Express as a proper division

m_2 = -1/ \frac{4}{3}

Convert to *

m_2 = -1* \frac{3}{4}

m_2 = -\frac{3}{4}

b.\ m = \frac{3}{7}

m_2 = -\frac{1}{m}

Substitute 3/7 for m

m_2 = -\frac{1}{3/7}

Express as a proper division

m_2 = -1/ \frac{3}{7}

Convert to *

m_2 = -1* \frac{7}{3}

m_2 = -\frac{7}{3}

c.\ m = 4

m_2 = -\frac{1}{m}

Substitute 4 for m

m_2 = -\frac{1}{4}

d.\ m = \frac{1}{3}

m_2 = -\frac{1}{m}

Substitute 1/3 for m

m_2 = -\frac{1}{1/3}

Express as a proper division

m_2 = -1/ \frac{1}{3}

Convert to *

m_2 = -1* \frac{3}{1}

m_2 = -\frac{3}{1}

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3 years ago
Question:
Minchanka [31]

Answer:

18 feet

Step-by-step explanation:

9/12 = 0.75

24 x 0.75 = 18

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-6x + 5 > -1
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Are these triangles congruent ?<br><br> And what is the theorem ?
ahrayia [7]

Answer:

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