Answer:
(47+37)(47-37)
Step-by-step explanation:
47^2-37^2 is a difference of two squares. a^2-b^2 = (a+b)(a-b) so this expression can be factored to (47+37)(47-37) = (84)(10) = 840
<span>the sequence is geometric, with the common ratio being 1/6 (48 * 1/6 = 8
The formula for a geometric sequence is cr^n where "c" is a constan</span>t <span> and "r" is the common ratio
=48(1/6)^n.
A geometric series converges only if the absolute value of the common ratio is < It diverges if the ratio is >or equal to 1.
the ratio is 1/6, so the sequence converges.
Now in this case, the limit seems to approach 0,
values can only keep getting smaller.
If the limit approaches 0, then the series will converge to a definite sum
S = c / (1 - are)
S = 48 / (1 - 1/6)
S = 57.6
series converges, has a limit of 0,
sum of 57.6.
hope this helps</span>
Answer:
Consider the proposition C=(p∧q∧¬r)∨(p∧¬q∧r)∨(¬p∧q∧r)
Step-by-step explanation:
This compound proposition C uses the outer disjunction (∨) then the proposition is true if and only if one of the three propositions (p∧q∧¬r),(p∧¬q∧r),(¬p∧q∧r) is true.
First, it is impossible that two or three of these propositions are simultaneously true. For example, if (p∧q∧¬r) and (p∧¬q∧r) are both true, then ¬r is true (from the first conjuntion) and r is true (from the second one), a contradiction. All the other possibilities can be discarded reasoning in the same way.
Since these propositions are mutually excluyent, C is true if and only if exactly one of the three propositions is true (and false otherwise). This can only happen if exactly two of p,q, and r are true and the other one is false. For example, (p∧q∧¬r) is true when p and q are true, and r is false.
Answer:
21
Step-by-step explanation: