Answer:
The z-score for a data value of 121 is -2.29.
Step-by-step explanation:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the z-score for a data value of 121.
This is Z when X = 121. So



The z-score for a data value of 121 is -2.29.
Answer:
3 1/3
Step-by-step explanation:
2 + (-2/3)² ÷ 1/3
2 + 4/9 ÷ 1/3
2 + 4/9 × 3/1
2 + 12/9 = 2 + 4/3 = 2 + 1 1/3
= 3 1/3
Answer:
There are 2.22 grams of clay are in each pot.
Step-by-step explanation:
Given:
Dakota has 4/10 kg of clay. He divides the clay to make 888 equal-sized pots.
Now, to find the number of grams of clay are in each pot.
Dakota has clay =
So, by using conversion factor we convert it into grams:
Quantity of clay he has = 400 grams.
Number of equal-sized pots to make = 888.
Now, to get the quantity of grams of clay are in each pot we divide number of equal-sized pots to make by quantity of clay he has:
Therefore, there are 2.22 grams of clay are in each pot.
Answer:
552
Step-by-step explanation:
This is a problem of permutation which can be solved by rule of fundamental counting principle.
This principle states that if there "m" ways of doing one thing and "n" ways of doing other. Then no. of ways in which both the things can be done together is "m*n". This can be extended for m, n, p,r, s things and so on.
example: if there are 5 shirts and 3 trousers then number of ways in which the shirts and trousers can be worn is 5*3 = 15 ways.
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The given problem is on similar concepts.
here 6 short stories, 4 novels, and 23 poems have to be assigned to his class.
Thus it can be done in 6*4*23 = 552 ways.