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Tamiku [17]
4 years ago
9

I don't know how to simplify this question. Is quotient rule necessary?

Mathematics
1 answer:
barxatty [35]4 years ago
5 0

Answer:

The answer to your question is \frac{(x+1)^{2}(x - 23)}{(x-7)^{3}}, because the directions says to give the answer in factor form.

Step-by-step explanation:

                               \frac{3(x+1)^{2}(x-7)^{2}- (x+1)^{3}(2)(x - 7)}{(x - 7)^{4}}

Factor like terms   (x - 7)(x + 1)²

                               \frac{(x - 7)(x + 1)^{2}[3(x - 7) - 2(x + 1)}{(x - 7)^{4}}

Simplify

                              \frac{(x+1)^{2}[3(x - 7) - 2(x+1)]}{(x-7)^{3}}

Expand

                              \frac{(x+1)^{2}[3x - 21 -2x - 2]}{(x - 7)^{3}}

Simplify

                             \frac{(x + 1)^{2}(x - 23)}{(x - 7)^{3}}    

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Answer:

-3.2

Step-by-step explanation:

-16/5=-3.2

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An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the
MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?

b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}=  1.45

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}=  3.59

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Simplify.<br><br><br><br>1/2−3(1/2+1)2
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The answer is -17/2. B
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