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Tamiku [17]
3 years ago
9

I don't know how to simplify this question. Is quotient rule necessary?

Mathematics
1 answer:
barxatty [35]3 years ago
5 0

Answer:

The answer to your question is \frac{(x+1)^{2}(x - 23)}{(x-7)^{3}}, because the directions says to give the answer in factor form.

Step-by-step explanation:

                               \frac{3(x+1)^{2}(x-7)^{2}- (x+1)^{3}(2)(x - 7)}{(x - 7)^{4}}

Factor like terms   (x - 7)(x + 1)²

                               \frac{(x - 7)(x + 1)^{2}[3(x - 7) - 2(x + 1)}{(x - 7)^{4}}

Simplify

                              \frac{(x+1)^{2}[3(x - 7) - 2(x+1)]}{(x-7)^{3}}

Expand

                              \frac{(x+1)^{2}[3x - 21 -2x - 2]}{(x - 7)^{3}}

Simplify

                             \frac{(x + 1)^{2}(x - 23)}{(x - 7)^{3}}    

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Answer:

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Step-by-step explanation:

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3 years ago
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Ivanshal [37]
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that is the equation of your line. however, if you want to graph it, this doesn't really make much sense to you. convert it to slope-intercept form, y = mx + b, by solving for y.

y - 2 = -3(x + 5) ... distribute -3
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to graph this, and any other y = mx + b equation, you want to start with your y-intercept if it's present. your y intercept here is -13, which means the line you wasn't to graph crosses the y-axis at y = -13, or (0, -13). put a point there.

after you've plotted that point, you use your slope to graph more. remember that your slope is "rise over run"--you rise up/go down however many units, you run left/right however many units. if your slope is -3, you want to go down 3 units, then go to the right 1 unit. remember that whole numbers have a 1 beneath them as a fraction. -3/1 is your rise over 1.
6 0
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madam [21]

We need to use the formula for simple interest which is
I= prt
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Substituting the numbers into the simple interest formula, we get
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