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4 years ago

14

What is the probability that your name will be drawn first, and NOT replaced , from each bag.?

1 answer:

Alex17521 [72]4 years ago

8 0

2/20 I'm pretty sure

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A triangular field has sides 218.5 and 213.3 and the angle between them measures 58.96°. Find the area of the field.

Zolol [24]

Answer:

The area of the field = 19966.21 units²

Step-by-step explanation:

* Lets explain how to find area of a triangle by trigonometry rule

- In any triangle if you have the lengths of two sides and the measure

of the including angle between these two sides, then the area of the

triangle is A = $\frac{1}{2}s_{1}s_{2}sin\alpha$ , wher α is the

including angle between them

* Lets solve the problem

∵ The field is shaped triangle

∵ The lengths of two sides of the field are 218.5 and 213.3

∴ s1 = 218.5

∴ s2 = 213.3

∵ The measure of the angle between the two sides is 58.96°

∴ α = 58.96°

- Lets find the area using the rule of trigonometry

∴ $A=\frac{1}{2}(218.5)(213.3)sin(58.96)=19966.21$

∴ The area of the field = 19966.21 units²

4 0

3 years ago

Jennie's car averages 35 mile p gallon , gas is 2.56 p gallon what is the cost p mile ?

noname [10]

Answer:12

Step-by-step explanation:

Trust me bro

4 0

3 years ago

There are three power plants [X, Y, Z] that at any given time each one either generates electricity or idles. Event A is that pl

insens350 [35]

We're told that

$P(A\cap B)=0.15$

$P(A\cup B)^C=0.06\implies P(A\cup B)=0.94$

$P(B\mid A)=P(B^C\mid A)=0.5$

where the last fact is due to the law of total probability:

$P(A)=P(A\cap B)+P(A\cap B^C)$

$\implies P(A)=P(B\mid A)P(A)+P(B^C\mid A)P(A)$

$\implies 1=P(B\mid A)+P(B^C\mid A)$

so that $B\mid A$ and $B^C\mid A$ are complementary.

By definition of conditional probability, we have

$P(B\mid A)=P(B^C\mid A)$

$\implies\dfrac{P(A\cap B)}{P(A)}=\dfrac{P(A\cap B^C)}{P(A)}$

$\implies P(A\cap B)=P(A\cap B^C)$

We make use of the addition rule and complementary probabilities to rewrite this as

$P(A\cap B)=P(A\cap B^C)$

$\implies P(A)+P(B)-P(A\cup B)=P(A)+P(B^C)-P(A\cup B^C)$

$\implies P(B)-[1-P(A\cup B)^C]=[1-P(B)]-P(A\cup B^C)$

$\implies2P(B)=2-[P(A\cup B)^C+P(A\cup B^C)]$

$\implies2P(B)=[1-P(A\cup B)^C]+[1-P(A\cup B^C)]$

$\implies2P(B)=P(A\cup B)+P(A\cup B^C)^C$

$\implies2P(B)=P(A\cup B)+P(A^C\cap B)\quad(*)$

By the law of total probability,

$P(B)=P(A\cap B)+P(A^C\cap B)$

$\implies P(A^C\cap B)=P(B)-P(A\cap B)$

and substituting this into $(*)$ gives

$2P(B)=P(A\cup B)+[P(B)-P(A\cap B)]$

$\implies P(B)=P(A\cup B)-P(A\cap B)$

$\implies P(B)=0.94-0.15=\boxed{0.79}$

8 0

3 years ago

X/2.5=20 what does x equal?

sesenic [268]

This is a one-step equation. All you need to do is multiply the 2.5 over to the 20 to get x by itself. x=50 Hope this helps!

5 0

3 years ago

Read 2 more answers

Which is the slope-intercept form of an equation for the line containing

Thepotemich [5.8K]

Answer:

The answer is letter A.

Step-by-step explanation:

y=mx+b

-3=(-1)(0)+b

-3=0+b

0 0

-3=b

y= -1x-3

6 0

3 years ago