V^2 = u^2 - 2gh; where v is the final speed, u is the initial speed, g = 9.8 m/s = 0.54 ft/min is the accerelation due to gravity, h = height.
At the maximum height, the final speed is 0.
u^2 = 2gh = 2 x 0.54 x 36 = 38.58
u = sqrt(38.58) = 6.21 ft/min
Therefore, the stne should be thrown with 6.21 ft/min
Answer: https://www.coursehero.com/file/36434863/math-124docx/
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X^2 + 9x -10 = (x -1)(x +10) = (x +(-1)) (x + 10)
p = -1 and q = 10
answer is A.
17 Is not the right answer whats the right answer
