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3 years ago

(3 pt) Which property does the statement illustrate? Column A Column B

Mathematics

1 answer:

DanielleElmas [232]3 years ago

8 0

1. B
2. A
3. B
4. A
Is your answer

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What is the area of the figure below?

fgiga [73]

Answer:

Option a 26 inches square

Step-by-step explanation:

Given in the picture is a triangle with 3 sides as 10.8 inches, 5 inches and base =10+3 = 13 inches

The altitude for base 13 inches is shown as 4 inches.

We know that for any triangle area

=1/2 * base * height

Here base = 13 and height = 4

Hence area = 1/2 (13)(4) = 26 inches square

Answer is option a

---

This can be done in another way also

There are two triangles one with base 10 inches and height 3 inches and another with base 3 inches and height 4 inches

Area of combined figure = sum of area of two triangles

= 1/2 (10)(4) +1/2(3)(4) =

20+6

=26 square inches

4 0

3 years ago

Read 2 more answers

Brian invests £600 into his bank account.

Savatey [412]

Answer:

It will be £2520

Step-by-step explanation:

3.2=
$\frac{16}{5}$
$\frac{16}{5} \times 100 = 320$
320
$320 \times 6 = 1920$
$1920 + 600 = 2520$

7 0

3 years ago

Combining like terms with rational coefficients <br> 7/8m+9/10-2m-3/5

nikklg [1K]

Answer:

Ah yes, one of my favorite topics.

Step 1: Which ever fraction comes first, you will solve it first. For this question, focus on doing $\frac{7}{8}m-2m$ first. Afterwards, do $\frac{9}{10}-\frac{3}{5}$

Step 2: First one equals to 1.125. Next, find the LCD (lowest common dominator, which is 10). $\frac{9}{10} -\frac{6}{10}=\frac{3}{10}$

Step 3: 1.125+3/10

7 0

3 years ago

Help me out please!!

Alexeev081 [22]

Answer:

Form: 2^7, 2^7 = 128

Step-by-step explanation:

You cannot multiply exponent, you must add the exponents.

4 + 3 = 7.

Keep the base the same.

Then find what 2^7 is.

Multiply:

2 x 2 x 2 x 2 x 2 x 2 x 2.

2 x 2 =

4 x 2 =

8 x 2 =

16 x 2 =

32 x 2 =

64 x 2 =

128.

4 0

3 years ago

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I need help with #11

Troyanec [42]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template in mind, let's take a peek at this function

$\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}$

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically

8 0

3 years ago

Read 2 more answers