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astra-53 [7]
3 years ago
8

Which of the following is the quadratic parent function?

Mathematics
1 answer:
kipiarov [429]3 years ago
8 0

Answer:

F(x)=x^2

Step-by-step explanation:


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Can someone list the coordinates of jk?
Ganezh [65]

Answer:

j= (-2,2)

k=(2,1)

Step-by-step explanation:

8 0
3 years ago
Find the radius of a circle that has a circumference of 1671.
son4ous [18]

Answer:

r=8

Step-by-step explanation:

Given formula:

r = C / 2π

It is given that C = 16π

hence

r = 16π / 2π = 8

8 0
3 years ago
Part A
nydimaria [60]

Answer:

1) D

2) 10

Step-by-step explanation:

sin(30) = opposite/hypotenuse

sin(30) = 5/x

½ = 5/x

x = 5/0.5

x = 10

5 0
3 years ago
Solve for w.<br> 2w=12-4w<br> Simplify your answer as much as possible.
aev [14]
So we have an equation:
2w=12-4w
Firstly, let's simplify, and divide all terms by 2:
w=6-2w
Now, we add 2w over to the other side:
3w=6
And finally, we divide both sides by 3:
w=2
Hope this helps!
6 0
3 years ago
The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin
quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

<u>So, </u>According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of <u>The inscribed circle</u>

<u>So, the center of The inscribed circle is the point S</u>

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

<u>So,</u> According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of <u>The circumscribed circle</u>

<u>So, the center of The circumscribed circle is the point P</u>

5 0
3 years ago
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