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kaheart [24]
3 years ago
9

Explain why 51 is not a prime number​

Mathematics
2 answers:
Levart [38]3 years ago
6 0

Step-by-step explanation:

51 is not a prime number because it is divisible by 1,3 and 17

and we know prime number are only those number who arenot divisible by any other number except 1

aleksklad [387]3 years ago
3 0

Answer:

57 is divisible by 1,3,19 and 57

Step-by-step explanation:

A prime number is a number that is divisible only by 1 and itself; and 57 is not among the numbers like 2,3,5,7,11 etc

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The volume of the cylinder is 392 cm cubed work out the length
Alik [6]
Well if you are given the radius, you can solve for it. As the volume of a cylinder is area of the base which is a circle times it height.

B • h = Pi r ^2 • h = 392 cm^3.

H = 392/Pi r^2.

This is the height or length.
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Lee and barry play a trivia game in which questions are worth different numbers of points. If a question is answered correctly,
Genrish500 [490]
1st) 275+70-50      Lastly: Subtract  -350 - 295 = - 55
       
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In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is
zheka24 [161]

Answer:

f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

Step-by-step explanation:

Let:

M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y

This is and exact equation, because:

\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}

So, define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)

The solution will be given by:

f(x,y)=C_1

Where C1 is an arbitrary constant

Integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y):

f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}

Substitute into \frac{\partial f(x,y)}{\partial y} =N(x,y)

2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y

Integrate \frac{dg(y)}{dy} with respect to y:

g(y)=\int\ {8y} \, dy =4y^2

Substitute g(y) into f(x,y):

f(x,y)=2x^2+4y^2+2xy

The solution is f(x,y)=C1

f(x,y)=2x^2+4y^2+2xy=C_1

Solving y using quadratic formula:

y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

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Answer:

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Step-by-step explanation:

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