The number of customers I would have expected to win the prize is 6.
<h3>How many more customers would I have expected to win the prize?</h3>
Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.
Based on the probability, the number of customers I would have expected to win: 0.18 x 300 = 36
How many more people I would have expected to win : 36 - 30 = 6
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Answer:
50√3/3
Step-by-step explanation:
30-60-90 triangle
50:x = 2sqrt3 : 2
50*2 =100
100/2sqrt3 = 3
50√
3
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Answer:
The surface area of the pyramid in exact form is 64 + 
cm²
The approximated surface area of the pyramid is 174.9 cm²
Step-by-step explanation:
The surface area of the square pyramid is the sum of the area of the base and the area of the four triangular faces
In Δ EFD
∵ m∠EFD = 90°
∵ m∠FDE = 60°
∵ ED = 8 cm
- By using sine ratio to find FE
∵ sin(∠FDE) = 
∴ sin(60) = 
- Multiply both sides by 8
∴ FE = 8 sin(60°)
∴ FE = 
cm
In Δ AED
∵ AE = ED
∵ m∠D = 60°
- In any isosceles Δ if measure of an angle is 60, then the
triangle is equilateral Δ
∴ Δ AED is an equilateral Δ
∴ AD = 8 cm
∵ The pyramid has 4 identical triangular faces
∵ Area of each Δ = 
× base × height
∵ AD is the base and FE is the height
∴ Area of each Δ = × 8 ×
∴ Area of each Δ = 
cm²
∵ Surface area of the pyramid = Area of base + 4 area of a Δ
∵ Area of base = 8²
∴ Area of base = 64 cm²
∴ Surface area of the pyramid = 64 + 4 ×
∴ Surface area of the pyramid = 64 +
The surface area of the pyramid in exact form is 64 + cm²
The approximated surface area of the pyramid is 174.9 cm²
Answer:
3 meters
Step-by-step explanation:
We are told that ...
the radius of circle P is half the radius of circle Q.
The same relation applies to any corresponding linear measures of these circles, so we can also say ...
the diameter of circle P is half the diameter of circle Q
the diameter of circle P is half of 6 meters, so is 3 meters
