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dalvyx [7]
3 years ago
15

Three sisters each have a collection of high-heel shoes. Helen has 10 more pairs of shoes than Betty. Natalie has three times as

many pairs of shoes as Helen. How many pairs of high-heel shoes does each sister have if together they have a total of 65 pairs?
Mathematics
1 answer:
GaryK [48]3 years ago
5 0

Answer:

Betty has 5 shoes, Helen has 15 shoes, and Natalie has 45 shoes.

Step-by-step explanation:

we can first try to solve this by assigning the sisters different number of shoes. lets give betty 0 shoes, Helen 10 shoes, and Natalie 30 shoes. this does follow the equation, however it does not equal 65.

what if we gave betty 5 shoes, Helen 15 shoes, and Natalie 45 shoes. This does follow the equation, because Helen has 10 more shoes than betty, and Natalie has 3 times more shoes than Helen. 5+15+45=65, So we have our answer!

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JulsSmile [24]

Answer:

a) test statistic = 2.12

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c) we reject the Null hypothesis

Step-by-step explanation:

Given data :

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p = x / n = 115 / 200 = 0.575

significance level ( ∝ ) = 0.1

<em>aim : test whether the proportion of girls births after the treatment is greater than 50% that occurs without any treatment </em>.

<u>A) Determine the test statistic </u>

H0 : p = 0.5

Ha : p > 0.5

to determine the test statistic we will apply the z distribution at ( ∝ ) = 0.1

Z - test statistic = ( 0.575 - 0.5)  / \sqrt{0.5*0.5 / 200}  = 2.12

<u>b) determine the p-value</u>

The P-value can be determined using the normal standard table

P-value = 1 - p(Z< 2.12 )  =  1 - 0.9830 = 0.017

c) Given that the p value ( 0.017 ) < significance level ( 0.1 )

we will reject the H0 because there is evidence showing that proportion of girls birth is > 50%

3 0
3 years ago
Y = -3x + 5? *<br> What’s the slope of the equation y =-3x+5
Crazy boy [7]

Answer:

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Step-by-step explanation:

The formula is y= mx + b

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Therefore, the slope is -3

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Step-by-step explanation:

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devlian [24]
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Given the volume of Figure A is 512cm ^3and Figure B is 343cm^3, find the ratio of the perimeter from Figure A to Figure B.
sp2606 [1]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\[2em] \begin{array}{ccccllll} &\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\ \cline{2-4}&\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}\\\\[-0.35em] ~\dotfill

\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{\textit{figure A}}{\textit{figure B}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{512}}{\sqrt[3]{343}}\qquad \begin{cases} 512=&2^9\\ &2^{3\cdot 3}\\ &(2^3)^3\\ 343=&7^3 \end{cases}\implies \cfrac{s}{s}=\cfrac{\sqrt[3]{(2^3)^3}}{\sqrt[3]{7^3}} \\\\\\ \cfrac{s}{s}=\cfrac{2^3}{7}\implies \cfrac{s}{s}=\cfrac{8}{7}\implies s:s = 8:7\impliedby \textit{ratio of the }\stackrel{sides~and}{perimeters}

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3 years ago
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