Answer:
x = -2, y = -1, z = 4
Step-by-step explanation:
4x + 6y - z=-18
z = 18 + 4
x + 6
y
3x +2y - 4z = -24
z = 6 + (3x)/
4 + y
/2
- 5x + 3y + 2z = 15
z = 15/2 + (5x)/2 - (3y)/2
18 + 4
x + 6
y = 6 + (3x)/
4 + y
/2 = 15/2 + (5x)/2 - (3y)/2
x = -22y/13 - 48/13
4(-22y/13 - 48/13) + 6y - (15/2 + (5(-22y/13 - 48/13))/2 - (3y)/2) = -18
Compute the output value of the variables x and y with respect to the input values of x, y, and z coefficients.
Answer:
x = 34
Step-by-step explanation:
x and 146 are supplementary angles so they add to 180 degrees
x+146 = 180
Subtract 146 from each side
x+146-146= 180-146
x =34
Answer:
Step-by-step explanation:
Hello!
The objective is to estimate the average time a student studies per week.
A sample of 8 students was taken and the time they spent studying in one week was recorded.
4.4, 5.2, 6.4, 6.8, 7.1, 7.3, 8.3, 8.4
n= 8
X[bar]= ∑X/n= 53.9/8= 6.7375 ≅ 6.74
S²= 1/(n-1)*[∑X²-(∑X)²/n]= 1/7*[376.75-(53.9²)/8]= 1.94
S= 1.39
Assuming that the variable "weekly time a student spends studying" has a normal distribution, since the sample is small, the statistic to use to perform the estimation is the student's t, the formula for the interval is:
X[bar] ±
* (S/√n)

6.74 ± 2.365 * (1.36/√8)
[5.6;7.88]
Using a confidence level of 95% you'd expect that the average time a student spends studying per week is contained by the interval [5.6;7.88]
I hope this helps!
The full price is $82, (100%), the discounted price is $65.60, (?%)
So lets see something:
$82 ------------- 100%
$65.60 --------------- x%
Multiply in cross
82.x = 65,60 . 100
82x = 6560
Divide both sides by 82
82x/82 = 6560/82
x = 80
So the discounted price is equal to 80% of the initial price
100% - 80% = 20% so the discount is 20%