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julsineya [31]
3 years ago
7

5 STARS!! PLEASE HELP

Mathematics
1 answer:
erica [24]3 years ago
7 0

Answer:

Choice 1

Step-by-step explanation:

Took the quiz and got this as the right answer :)

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A side of the triangle below has been extended to form an exterior angle of 128°. Find the value of x.
denis23 [38]

Answer:

x = 104

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles

24+x = 128

Subtract 24 from each side

24+x-24 =128 -24

x =104

3 0
3 years ago
What is the least common multiple of 12 and 11?
blsea [12.9K]
132, to sum up, the Lcm Of 11 and 12 is 132
8 0
3 years ago
Read 2 more answers
Can anyone help me find the coordinates (?,?) given that the shape is a parallelogram? (15 points)
xxTIMURxx [149]

The missing coordinates of the parallelogram is (m + h, n).

Solution:

Diagonals of the parallelogram bisect each other.

Solve using mid-point formula:

$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right  )

Here x_1=m, y_1=n, x_2=h, y_2=0

              $=\left( \frac{m+h}{2}, \frac{n+0}{2}\right  )

$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right  )

<u>To find the missing coordinate:</u>

Let the missing coordinates by x and y.

Here x_1=0, y_1=0, x_2=x,  y_2=y

$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{x}{2}, \frac{y}{2}\right  )

Now equate the x-coordinate.

$ \frac{m+h}{2}=\frac{x}{2}

Multiply by 2 on both sides of the equation, we get

m + h = x

x = m + h

Now equate the y-coordinate.

$\frac{n}{2} =  \frac{y}{2}

Multiply by 2 on both sides of the equation, we get

n = y

y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

5 0
3 years ago
2.
Virty [35]

Answer:

1/9 is probably most likely the correct answer

3 0
3 years ago
How many real zeros does the function graph below have?
Nostrana [21]

Answer:

Step-by-step explanation:

If the graph crosses the x-axis and appears almost linear at the intercept, it is a single zero. If the graph touches the x-axis and bounces off of the axis, it is a zero with even multiplicity. If the graph crosses the x-axis at a zero, it is a zero with odd multiplicity.

6 0
3 years ago
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