Answer:
girl i am taking a test right now and this question is on it and im strugglin
Step-by-step explanation:
Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:
Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
ANSWER:
12/25 = sinD*CosD
3/5 = SinD
16/15 = CosC*tanD
4/5 = tanC*tanD
STEP BY STEP EXPLANATION:
Finding the angles
Finding angle BCD
Sin(90)/5=Sin(BCD)/3
3sin(90)=5Sin(BCD)
3sin(90)/5=Sin(BCD)
sin^-1(3sin(90)/5) = /BCD
36.86989765 degrees = /C
Finding angle /CDB
Sin(90)/5=Sin(CDB)/4
Sin^-1(4sin(90)/5) = /CDB
53.13010235 degrees = /D
Evaluate the given question:
SinD=Sin(53.13010235)=0.8
SinC=Sin(38.86989765)=0.600000001
SinD*CosD = 0.48
TanC*TanD = 1
CosC*TanD = 1.066666666
FINAL EVALUATION
12/25 = 0.48
3/5 = 0.6
16/15 = 1.066666667
4/5 = 0.8
FINAL ANSWER
12/25 = SinD*CosD
3/5 = SinC
16/15 = CosC*TanD
4/5 = SinD
Hopefully it was useful :)
1.) 3/4>-5/6 (positive > negative)
Answer is b.>
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b.>
c.=
2.) -1 3/4 < 3/4
Answer is a.<
a.<
b.>
c.=
3.) 2 3/4 >2 4/6 (3/4 >0.75; and 4/6 = 0.6667)
Answer is b.>
a.<
b.>
c.=
Answer:
A, B and E
Step-by-step explanation:
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