I’m not sure I understand what’s going on here. But if you’re saying x=1, and the problem is 4x=?. Then 4(1)=4
A box-and-whisker plot shows 5 number summary: Class A Class B1) minimum value 65 562) 1st quartile 66 793) median 81 914) 3rd quartile 89 945) maximum value 95 100
Interquartile range = 3rd Quartile - 1st Quartile Class A: 89 - 66 = 23Class B: 94 - 79 = 15
IQR indicates the spread of the of the scores over the median. Class A has a spread that his more than 50% of the scores of Class B.
Hope this helps!! :)
Answer:
<u>A. p(hat) = .139</u>
We divide our sample population by the amount who tested positive. 14851/107109 = .139.
<u>B. 1.62 million</u>
We just multiply the p times the population. 11.69 M * .139 = 1.62 M
<u>C. No</u>
It depends upon the sample method. From what I can tell, I assume all conditions are met and it was not biased.
If it wasn't random, that is a problem, but we aren't given this information.
We can test if it's small enough. It can't be larger than 10% of the population. 107109 * 10 < 11.69 million, so it's small enough.
We can also test if it's large enough. np and nq must be greater than 10. 107100 * .139 > 10, 107100 * .861 > 10.
Input negative 18 into x and distribute. on both sides of the equal sign you should get 70=70
