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olga_2 [115]
3 years ago
11

the zeros of a parabola are -4 and 2, and (6, 10) is a point on the graph. which equation can be solved to determine the value o

f a in the equation of the parabola? brainly
Mathematics
2 answers:
natka813 [3]3 years ago
7 0
Sure this question comes with a set of answer choices.

Anyhow, I can help you by determining one equation that can be solved to determine the value of a in the equation.

Since, the two zeros are - 4 and 2, you know that the equation can be factored as the product of (x + 4) and ( x - 2) times a constant.  This is, the equation has the form:

y = a(x + 4)(x - 2)

Now, since the point (6,10) belongs to the parabola, you can replace those coordintates to get:

10 = a (6 + 4) (6 - 2)

Therefore, any of these equivalent equations can be solved to determine the value of a:

10 = a 6 + 40) (6 -2)

10 = a (10)(4)

10 = 40a
ad-work [718]3 years ago
4 0

Answer:

10 = a(6 + 4)(6 – 2)

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katovenus [111]
   
\displaystyle\\
1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) = ? \\  \\ 
1 \frac{2}{5} = \frac{1\times 5+2}{5}=\boxed{\frac{7}{5}} \\  \\ 
-5 \frac{1}{2} =-5 -\frac{1}{2} = \frac{-5\times2-1}{2} =\frac{-10-1}{2}=\frac{-11}{2}= \boxed{-\frac{11}{2} }\\  \\ \texttt{OR} \\  \\ 
-5 \frac{1}{2} = -\Big(5 \frac{1}{2} \Big)= -\Big( \frac{5\times2+1}{2} \Big)=-\Big( \frac{11}{2} \Big)= \boxed{-\frac{11}{2} }


\displaystyle\\
\Longrightarrow ~~1 \frac{2}{5} +\Big(-5 \frac{1}{2} \Big) =\frac{7}{5} -\frac{11}{2} = \frac{7\times 2}{5\times 2} -\frac{11\times 5}{2\times 5} = \\  \\ 
= \frac{14}{10} -\frac{55}{10} = \frac{14-55}{10} =\frac{-41}{10} = -\frac{41}{10}=-\frac{40+1}{10}=\boxed{\boxed{-4\frac{1}{10}}}



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