This is an arithmetic sequence with first term (a) = 11, number of terms (n) = 57, sum of nth term (Sn) = 19,779.
Let the amount of money she saved more each month be d, then
Sn = n/2(2a + (n - 1)d)
19,779 = 57/2(2(11) + (57 - 1)d)
19,779 = 28.5(22 + 56d)
19,779 = 627 + 1,596d
19,779 - 627 = 1,596d
d = 19,152/1,596 = 12
Therefore, she saved $12.00 more each month.
Answer:
32
Step-by-step explanation:

Answer: The margin of error = 
Step-by-step explanation:
Given
Sample size (n) = 1000
Population proportion = 0.4
= 1 - confidence level
= 1 - 0.95
= 0.05




= 0.03
The margin of error change to
to 
The total cost will be $20.21 because if u do $0.44×16 it will be $7.26 then, you will add $7.26+$12.95 together and get $20.21.