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Damm [24]
3 years ago
9

Determine whether the results below appear to have statistical​ significance, and also determine whether the results have practi

cal significance. In a study of a weight loss​ program, 77 subjects lost an average of 4141 lbs. It is found that there is about a 4040​% chance of getting such results with a diet that has no effect. Does the weight loss program have statistical​ significance?
Mathematics
1 answer:
NISA [10]3 years ago
4 0

Answer:

No, the weight loss program doesn't have statistical​ significance.

Step-by-step explanation:

We are given that in a study of a weight loss​ program, 7 subjects lost an average of 41 lbs.

It is found that there is about a 40% chance of getting such results with a diet that has no effect.

Firstly, statistical significance means that the event is sure to be happen and there is a proper statistical calculation behind it.

But here it is stated that there is a 40​% chance of getting such results with a diet that has no effect which means that the event is unlikely to happen by chance and it is just a prediction so, the weight loss program is not statistically significant.

Now, practically significant means that there is a large difference in the subjects being tested.

Here, the weight loss program is considered to be practically significant because there is a large amount of weight loss of 43 lbs of the subjects which is a large amount.

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1:15

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2l+2w 10 feet by 3.5 feet
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Answer:

Step-by-step explanation:

Perimeter of rectangle =2l+2w

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5 0
3 years ago
A local car dealership sells Buicks and Hondas. The following data shows the number of buyers this month according to the brand
Lina20 [59]

Answer:

16%

Step-by-step explanation:

The data provided on brand purchased by age group is.

\begin{array}{ccc}Age&Buick&Honda\\Under\ 40&6&17\\40\ or\ older&19&8\end{array}

A total of 50 cars were sold this month.

Since the number of buyers 40 years or older that purchased a ​Honda is 8, the percentage is:

P=\frac{8}{50}=0.16=16\%

16% of buyers were 40 years or older and purchased a​ Honda.

8 0
3 years ago
Five times the sum of 173 and 32
Ipatiy [6.2K]
Hello!
173 + 32 = 205
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4 0
3 years ago
The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.
Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

V=\frac{4}{3}  \pi r^3

Substituting \pi=3.14 and r=5 , we get,

V=\frac{4}{3} (3.14)(125)

V=\frac{1580}{3}

V=523.3333 \ in^3

Rounding off to two decimal places, we have,

V=523.33 \ in^3

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = \frac{3}{4} (5)=3.75

Radius of the third sphere = \frac{3.75}{2} =1.875

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

V=\frac{4}{3}  \pi r^3

Substituting \pi=3.14 and r=1.875 , we get,

V=\frac{4}{3} (3.14)(1.875)^3

V=\frac{4}{3} (3.14)(6.59)

V=27.5901 \ in^3

Rounding off to two decimal places, we have,

V=27.59 \ in^3

Thus, the volume of the third sphere is 27.59 in³

4 0
4 years ago
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