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lara31 [8.8K]
4 years ago
14

What is the binary number for 18​

Mathematics
2 answers:
mart [117]4 years ago
7 0

Answer:

69

Step-by-step explanation:

Svetlanka [38]4 years ago
6 0

Answer:

10010 that's the answer

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In a class 22 of students, 14 have a brother and 9 have a sister. There are 2 students who do not have any siblings. What is the
djyliett [7]
I believe this is the way to solve it.
 22 - 2 = 20
 20 is 90.9% of 22
So the probability of choosing a student with a sibling at random should be 90.9% (or you can round up to 91%)

I hope this helps :)
5 0
4 years ago
Can someone help me on this asap.
Alina [70]

Answer:

<em>-6y = 12</em>

Step-by-step explanation:

      3x - 4y = 7

-     3x + 2y = -5

-----------------------

             -6y = 12

8 0
3 years ago
Identify the domain of the graphed function.
AURORKA [14]

Answer: Option A is correct

(-5,3) U (3,6]


Step-by-step explanation:

Domain of a function is the complete set of values that the independent variable can assume.

In the given graphed function we can see that the minimum value of independent variable (x) is -5 and the maximum value is 6, wherein the values -5 and 3 do not belongs to x.


This set of values is represented as

(-5,3) U (3,6]


Hope it helps.


Thank you.


8 0
3 years ago
Read 2 more answers
If an=24, which recursive formula could represent the sequence below? ...,24,88, 664, 8408A) An=(An-2)^2 + An-1 ; A1=2B) An= 3An
Rudik [331]

When we substitute n = 4, we get...

a_{n-3}=a_1\\ \\ a_{n-2}=a_2\\ \\ a_{n-1}=a_3\\ \\ a_n=a_4

Comparing the given sequence: 24, 88, 664, 8408, we get

a_{n-3}=a_1=24\\ \\ a_{n-2}=a_2=88\\ \\ a_{n-1}=a_3=664\\ \\ a_n=a_4=8408

We need to substitute the above values in each option and check which is TRUE.

----

<u>Option A</u>

a_n=(a_{n-2})^2+a_{n-1}, a_1=2\\ \\ a_n=(88)^2+664=7744+664\\\\a_n=8408 (TRUE)

<u>Option B</u>

a_n=3a_{n-1}+16\\ \\ a_n=3(664)+16\\\\a_n=2008 (FALSE)

<u>Option C</u>

a_n=(n)a_{n-1}-8\\ \\  a_4=(4)a_3-8=4(664)-8\\\\a_4=2648 (FALSE)

<u>Option D</u>

a_n=2a_{n-2}+7a_{n-1}\\ \\ a_n=2(88)+7(664)\\ \\ a_n=4824(FALSE)

Conclusion:

Option A is the correct answer.

6 0
4 years ago
Read 2 more answers
If <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%20%2B%20ib%7D%7Bc%20%2B%20id%7D%20" id="TexFormula1" title=" \frac{a + i
Simora [160]

Rewrite the given number as

\dfrac{a+ib}{c+id}=\dfrac{(a+ib)(c-id)}{(c+id)(c-id)}=\dfrac{ac+bd+i(bc-ad)}{c^2+d^2}

If it's purely real, then the complex part should be 0, so that

\dfrac{bc-ad}{c^2+d^2}=0\implies bc-ad=0\implies\boxed{ad-bc}

as required.

7 0
3 years ago
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