When y=2 and y=5
1. 2y-1 and (3y-5+y or 4y-5)
when y=2 ; 2(2)-1 = 3 and 4(2)-5=3
when y=5 ; 2(5)-1 = 9 and 4(5)-5=15
----nonequivalent-----
2.5y+4 and (7y+4-2y or 5y+4)
so you don't have to place any value in because 5y+4 and 7y+4-2y are equal,
whatever you place any value in, it will be all the same then
-----equivalent------
and no need to find more
Answer:

Step-by-step explanation:
1.Approach
To solve this problem, find the area of the larger circle, and the area of the smaller circle. Then subtract the area of the smaller circle from the larger circle to find the area of the shaded region.
2.Find the area of the larger circle
The formula to find the area of a circle is the following,

Where (r) is the radius, the distance from the center of the circle to the circumference, the outer edge of the circle. (
) represents the numerical constant (3.1415...). One is given that the radius of (8), substitute this into the formula and solve for the area,

3.Find the area of the smaller circle
To find the area of the smaller circle, one must use a very similar technique. One is given the diameter, the distance from one end to the opposite end of a circle. Divide this by two to find the radius of the circle.
8 ÷2 = 4
Radius = 4
Substitute into the formula,

4.Find the area of the shaded region
Subtract the area of the smaller circle from the area of the larger circle.


34 x 2 = 17 x 4
answer = 4
Answer:
I dont understand btw thanx for the points
Step-by-step explanation:
Answer:
The value of an appropriate test statistic for the car dealer to use is -4.
Step-by-step explanation:
The null hypothesis is:

The alternate hypotesis is:

The test statistic is:

In which X is the sample mean,
is the value tested at the null hypothesis,
is the standard deviation and n is the size of the sample.
In this problem:

Then



The value of an appropriate test statistic for the car dealer to use is -4.