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ollegr [7]
3 years ago
13

A straight line is drawn through the intersection of the two diagonals of a parallelogram. Prove that it exactly divides the par

allelagram into two equal parts by area.
Mathematics
1 answer:
zubka84 [21]3 years ago
3 0

Answer:

I dont understand btw thanx for the points

Step-by-step explanation:

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Tanzania [10]
It is answer C because 59/18 is equal to 3 5/18
6 0
3 years ago
Solve the equation 6.5 = -3+n
siniylev [52]

Answer:

9.5 = n

Step-by-step explanation:

6.5 = -3 + n

+3     +3            Add 3 to both sides

9.5 = n

If this answer is correct, please make me Brainliest!

7 0
3 years ago
Read 2 more answers
Solve for the unknown by using the additive inverse. Type the FULL answer in the box, without using any spaces (ex., X=5).
svlad2 [7]
Answer: Y=-1

Explanation: 2y-3=y-4 (add three on both sides)
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8 0
3 years ago
PLEASE HELP!!! 14 POINTS!
Pepsi [2]
Area=1/2bh


add them
(1/2)ab+(1/2)c^2+(1/2)ab=
ab+(1/2)c^2
ab+(1/2)(a^2+b^2)
not sure which option to pick there are different preferences on what counts as 'simplified'




4. find area
area=LW
area=105*45=4725
depends on the area of the signs
answer is
4725/(areaof1sign)
anyway, round down your answer because you will have an incomplete sign if you don't




5. area=pir^2
1/2 of it is
area=1/2pir^2
area=(1/4)^2pir^2
area=pi((1/4)r)^2
the radius is now 1/4 of what it was originally, meaning that the diameter is also 1/4 of what it is now
we need to know diamater
answer is 1/4 of current diameter




3. unclear

4. area of 1 sign not given, answer is 4725/(areaof1sign), rounded DOWN to nearest integer

5. (404 error, diameter not found) answer is 1/4 of current diameter
8 0
3 years ago
Alexandra invested $800 in an account paying an interest rate3.1% compounded continuously. Assuming no deposits or withdrawals a
s2008m [1.1K]

\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$800\\ r=rate\to 3.1\%\to \frac{3.1}{100}\dotfill &0.031\\ t=years\dotfill &20 \end{cases} \\\\\\ A=800e^{0.031\cdot 20}\implies A=800e^{0.62} \\\\\\ A\approx 1487.14\implies A=\stackrel{rounded~up}{1500}

8 0
3 years ago
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