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mezya [45]
3 years ago
7

A grocery store sells bags of oranges in two different sizes the 3 pound bag $4 the 8 pound bag cost $9 which cost less

Mathematics
1 answer:
timofeeve [1]3 years ago
7 0

Answer:

The 8 pounds bag

Step-by-step explanation:

Case 1 :

a pound cost 4/3

case 2 :

a pound cost 9/8

4×8 > 9×3

then

\frac{4}{3} >\frac{9}{8}

Therefore the 8 pound bag costs less

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Step-by-step explanation:

23x - 15x = x-1

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8x - x = 1

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Read 2 more answers
1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING
iogann1982 [59]

If

y=\displaystyle\sum_{n=0}^\infty a_nx^n

then

y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n

The ODE in terms of these series is

\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0

\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0

\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}

We can solve the recurrence exactly by substitution:

a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0

\implies a_n=\dfrac{(-2)^n}{n!}a_0

So the ODE has solution

y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}

which you may recognize as the power series of the exponential function. Then

\boxed{y(x)=a_0e^{-2x}}

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Help please! Lily records the change in her dogs weight over 4 weeks what is the dogs average weekly weight change
madreJ [45]

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mabe divided by 2

Step-by-step explanation:

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