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kobusy [5.1K]
3 years ago
13

Subject differential equationDay. Month.Year. ..(y-secx) dx + tanxdy...o​

Mathematics
1 answer:
Colt1911 [192]3 years ago
8 0

(y-\sec x)\,\mathrm dx+\tan x\,\mathrm dy=0

Divide both side by \mathrm dx and rearrange terms to get a linear ODE;

\tan x\dfrac{\mathrm dy}{\mathrm dx}+y=\sec x

Multiply both sides by \cos x:

\sin x\dfrac{\mathrm dy}{\mathrm dx}+\cos x\,y=1

The left side can be condensed as the derivative of a product:

\dfrac{\mathrm d}{\mathrm dx}(\sin x\,y)=1

Integrate both sides, then solve for y:

\sin x\,y=x+C\implies\boxed{y(x)=x\csc x+C\csc x}

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igor_vitrenko [27]
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3 years ago
A man sells a type of nut for $7 per pound and a different one for $4.20 per pound, how much of each type should be used to make
qwelly [4]

Answer:

a type nut is 10 pounds

a different one is 14 pounds

Step-by-step explanation:

let a type of the nut be represented by t

Let a different one be represented by d

a type of nut cost $7 per pound

a different one cost $4.20 per pound

The cost of the mixture for 24 pounds = 5.37 * 24

= $128.88

t + d = 24 ........(1)

7t + 4.2d = 128.88 ..........(2)

From equation (1), t = 24 - d

Put t = 24 - d in equation 2

7(24 - d) + 4.2d = 128.88

168 - 7d + 4.2d = 128.88

168 - 2.8d = 128.88

-2.8d = 128.88 - 168

-2.8d = -39.12

d = -39.12 / -2.8

d= 13.97

d = 14 pounds

t = 24 - d

t = 24 - 14

t = 10 pounds

A type nut is 10 pounds. A different one is 14 pounds

5 0
3 years ago
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serg [7]
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Answer:

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