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frutty [35]
2 years ago
7

A prism with a square base has a height of 15cm and a volume of 735cm3. Find the length of each edge of the base.

Mathematics
1 answer:
denis-greek [22]2 years ago
6 0

Answer:

The length of each edge of the base is 7cm.

Step-by-step explanation:

The volume of a prism with square base is given by:

V = l^{2}h

In which l is the length of each edge of the base and h is the height.

A prism with a square base has a height of 15cm and a volume of 735cm3.

This means that V = 735, h = 15

So

V = l^{2}h

735 = 15l^{2}

l^{2} = \frac{735}{15}

l^{2} = 49

l = \pm \sqrt{49}

Length is a positive measure. So

l = 7

Volume in cm³, so the length of each edge is in cm.

The length of each edge of the base is 7cm.

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Write an equation of the line passing through the point (-8, -4) that is perpendicular to the line given by y= 1/6 x+3.
user100 [1]

Answer:

y+4=-6(x+8)  point-slope form

y=-6x-52 slope-intercept form

6x+y=-52 standard form

Step-by-step explanation:

Slope-intercept form of a line is y=mx+b where m is the slope and b is the y-intercept.

Lines that are perpendicular have opposite reciprocal slopes.

So the slope of y=(1/6)x+3 is 1/6.

The opposite reciprocal of (1/6) is -6.

So the equation for the line we are looking for is in the form:

y=-6x+b         (Since the slope of our new line is -6)

Now we want our line to go through (-8,-4).

So plug that in:

-4=-6(-8)+b

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Subtract 48 on both sides:

-52=b

The equation for the line we are looking for is

y=-6x-52.

Now you could do other forms.

Another one is point-slope form.

We already know it goes through (-8,-4) and a slope of -6.

Point slope form is: y-y1=m(x-x1) where m is the slope and (x1,y1) is a point on the line.

Plug in the information to get:

y-(-4)=-6(x-(-8))

y+4=-6(x+8)

I'm going to do one more form.

Standard form is ax+by=c where a,b,c are integers.

y=-6x-52

Add 6x on both sides:

6x+y=-52

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3 years ago
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