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3 years ago

7

How would you solve this(what is the equation of the line that passes through the point (3,4) and has a slope of -2/3?)//delta m

ath//

1 answer:

andre [41]3 years ago

6 0

Answer:

$y = -\frac{2}{3}x + 6$

Step-by-step explanation:

y = mx + b is the formula for slope intercept. What we can do is plug in the slope and coordinate points to find the y-intercept.

4 = $-\frac{2}{3}$ (3) + b

-2/3 times 3 is -2 so you can fill that in place.

4 = -2 + b

<u>+2 +2 </u>

6 = b

So the y-intercept is 6 now we can complete the equation.

$y = -\frac{2}{3}x + 6$

Hope that helps and have a great day!

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3 years ago

If f(1) = 10 and f(n) = f(n = 1) – 4 then find the value of f(5).

svetoff [14.1K]

Given:

$f(1)=10$ and $f(n)=f(n-1)-4$ .

To find:

The value of f(5).

Solution:

We have,

$f(n)=f(n-1)-4$

For $n=2$ ,

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$f(2)=f(1)-4$

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For $n=3$ ,

$f(3)=f(3-1)-4$

$f(3)=f(2)-4$

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For $n=4$ ,

$f(4)=f(4-1)-4$

$f(4)=f(3)-4$

$f(4)=2-4$

$f(4)=-2$

For $n=5$ ,

$f(5)=f(5-1)-4$

$f(5)=f(4)-4$

$f(5)=-2-4$

$f(5)=-6$

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3 years ago

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