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2 years ago

Solve the inequality. 4x + 1 < 8x - 3 < 4x + 5

Mathematics

1 answer:

Morgarella [4.7K]2 years ago

3 0

Answer:

1 <x <2

Step-by-step explanation:

4x + 1 < 8x - 3 < 4x + 5

Split into two inequalities

4x + 1 < 8x - 3 and 8x - 3 < 4x + 5

Do the first one first

4x + 1 < 8x - 3

Subtract 4x from each side

4x -4x + 1 < 8x-4x - 3

1 < 4x-3

Add 3 to each side

1+3 < 4x-3+3

4 < 4x

Divide by 4

4/4 <4x/4

1 <x

Now the other

8x - 3 < 4x + 5

Subtract 4x from each side

8x -4x-3 < 4x+5-4x

4x-3 < 5

Add 3 to each side

4x-3+3 < 5+3

4x<8

Divide by 4

4x/4 <8/4

x <2

Put them back together

1 <x <2

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If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248

$\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}$

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