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Anon25 [30]
4 years ago
9

Given that x and y are real numbers find the possible values of x and y if (x+y)+(x-y)i=7+3i

Mathematics
1 answer:
atroni [7]4 years ago
5 0

(x+y)+(x-y)i=7+3i

x+y =7

x-y =3

add these two equations together

x+y =7

x-y =3

------------------

2x = 10

divide by 2

x=5

x+y = 7

5+y =7

subtract 5 from each side

y =2

Answer: x=5

             y=2

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6 math books would be 126
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6 0
4 years ago
Which expression is equivalent to 4 square root 3^3 <br> A 3 3/4<br> B 3 4/3<br> C 4^1<br> D 4^3
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6 0
3 years ago
How many pounds and ounces are there in 26 oz?
a_sh-v [17]

1 pound = 16 ounces

_ pound = 26 ounces

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Hope this helps :)

5 0
3 years ago
Assume lim f(x)-6 and lim g(x)-9. Compute the following limit and state the limit laws used to justify the computation.
emmasim [6.3K]

Answer:

4

Step-by-step explanation:

<h3><u>some relevant limit laws</u></h3>

lim C = C where c is a constant.

lim( f(x)  + g(x)) =lim f(x) + lim g(x)

lim( f(x)g(x)) =lim f(x) * lim g(x)

lim( cg(x)) =clim g(x)

lim( f(x)/g(x)) =lim f(x) / lim g(x) if  lim g(x) is not equal to zero.

lim( f(x))^2 = (lim f(x) )^2

lim  square root( f(x)) = square root(lim f(x) )

\lim_{n \to 3} g(x)  = 9\\\\\lim_{n \to 3} f(x)  = 6\\\\ \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10} \\\\ = \lim_{n \to 3} \sqrt[3]{f(x)g(x) + 10}\\\\= \sqrt[3]{lim_{n \to 3}f(x) \times lim_{n \to 3}g(x) + 10}\\\\= \sqrt[3]{6 \times 9 + 10}\\\\= \sqrt[3]{64}

= 4

4 0
4 years ago
Solve the equation-10 +1 +7x =37
In-s [12.5K]

Answer:

x = 46/7

Step-by-step explanation:

Have a blessed day

5 0
3 years ago
Read 2 more answers
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