Answer:
Will have an expected value of the mean = 80 and a standard error of the mean = 5
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean 
and standard deviation 
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation 
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this problem, we have that:
n = 16
So the mean is 80 and the standard deviation is 
Will have an expected value of the mean = 80 and a standard error of the mean = 5
Answer:
Step-by-step explanation:
you know ; for all reals a ; cos(π/2 - a) = sin(a)
so : sin(5x+15) = cos(π/2-(5x+15) ) = cos(π/2-5x-15)
sin(5x+15)=cos(4x−6) eqivaut : cos(π/2-5x-15) = cos(4x−6)
note : cos(a)=cos(b) : a= b +2kπ or a= - b +2kπ ....k in Z
π/2-5x-15 = 4x−6 + 2kπ or π/2-5x-15 = - (4x−6) + 2kπ....k in Z
continue calculate : x .......
To determine the 5th term you need to find the 4th. This doesn’t work for all but for this one you just add a zero at the end. So the 4th term is 1,000 and that makes the 5th term 10,000
Answer:
.077
.64935
Step-by-step explanation:
Let F= failure
let S= severe
we are given that
p(F|S')= .03
p(F|S)= .5
For the first question we are looking for f
we can solve for it by using the law of total probability
so in theory we want
F∩S+F∩S'
Using the conditional probability formula we can solve for the intersections
.03*.9+.5*.1= .077
2.
For this question we are looking for S|F
to solve this use bayes thereom
(or 50/77)
I think the answer is -f, hope this helps!
