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aliya0001 [1]
3 years ago
13

Help ASAP before 2:10

Mathematics
2 answers:
kirill115 [55]3 years ago
5 0

Answer:3 choice

Step-by-step explanation:

When you have this || you put the opposite mark

Schach [20]3 years ago
5 0

Answer:

D

Step-by-step explanation:

-6

-2

|-4|

|-5|

6

The || means "absolute value". Thats the distance from 0 on a number line.

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Ne4ueva [31]

Answer:

x = -\frac{1}{3}, y = 2

Step-by-step explanation:

3x + 3y - 7 = 12x + y

6y - 12x - 1 = -45x

(3x - 12x) + (3y - y) = 7

(-12x + 45x) + 6y = 1

-3(-9x + 2y = 7)

33x + 6y = 1

27x - 6y = -21

33x + 6y = 1

60x = -20 -> x = -20/60 = -1/3

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3 years ago
What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth
uysha [10]

Answer:

The perimeter of the trapezoid is 38.25\ units

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

so

In this problem

P=QR+RS+ST+QT

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

Q(8, 8), R(14, 16), S(20, 16),T(22, 8)

step 1

Find the distance QR

Q(8, 8), R(14, 16)

substitute the values in the formula

d=\sqrt{(16-8)^{2}+(14-8)^{2}}

d=\sqrt{(8)^{2}+(6)^{2}}

d=\sqrt{100}

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step 2

Find the distance RS

R(14, 16), S(20, 16)

substitute the values in the formula

d=\sqrt{(16-16)^{2}+(20-14)^{2}}

d=\sqrt{(0)^{2}+(6)^{2}}

d=\sqrt{36}

RS=6\ units

step 3

Find the distance ST

S(20, 16),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-16)^{2}+(22-20)^{2}}

d=\sqrt{(-8)^{2}+(2)^{2}}

d=\sqrt{68}

ST=8.25\ units

step 4

Find the distance QT

Q(8, 8),T(22, 8)

substitute the values in the formula

d=\sqrt{(8-8)^{2}+(22-8)^{2}}

d=\sqrt{(0)^{2}+(14)^{2}}

d=\sqrt{196}

QT=14\ units

step 5

Find the perimeter

P=10+6+8.25+14=38.25\ units

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Step-by-step explanation:

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Answer:

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